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Thankk you soo muchh!! Goodluckk tooThey have said in the question that the cats without tails are always heterozygous.. so in cross 1: both parents are heterozygous..
and since the allele without tail is dominant, then each parent has the alleles Rr ..
when both are crossed: Rr x Rr
offsprings will be RR, Rr, Rr, rr
so there is 3/4 chance that the offspring is without a tail..
therefore (3/4) * 112 = 84
112 is the total number of osprings
and there is 1/4 chance that the offspring has tail
(1/4) * 112 = 28
then continue the calculation to find chi square