Challenging math questions paper 42

[mido4help]

The exam was quite easy but some parts are not easy
First the rod fit or not
Final part of cone (volume of shaded part)
probability of last part of culmutaive frequency
Last part of squence
angle between line and base

 

[Cozmo35d]

For the probability question I think it was 94/150 x 93/149 , I dont remember if it was 94,93, I forgot about the question.

 

[WayneRooney10]

For the probability question I think it was 94/150 x 93/149 , I dont remember if it was 94,93, I forgot about the question.

You got that RIGHT bro!!!

 

[Cozmo35d]

omg you're kidding, oh yesss, thankss for telling me man. Im ssooo happy now.

 

[Ramosk95]

The exam was quite easy but some parts are not easy
First the rod fit or not
Final part of cone (volume of shaded part)
probability of last part of culmutaive frequency
Last part of squence
angle between line and base

i wrote that it fits
for cone volumes its k^3 and then you subtract
probability its smthn with 1xxx over 3xxx idon't remember
angle between line and base i used tanx=1.7/2.5
sequences a=-.25 b=2.25

 

[Cozmo35d]

I wrote that it fits by placing it diagonally since it's 2.95 cm long and the diagonal line was 3 or something. I hope it's right.

 

[Zika9999]

For the probability question I think it was 94/150 x 93/149 , I dont remember if it was 94,93, I forgot about the question.

I made it 95/150 x 94/149

 

[Dooouuu]

what about the median interval , LCM and HCF , .............

Ramosk95 : are u sure from ur answer at the last question ??

 

[Cozmo35d]

Yeah I think yours and mine are right cuz IM not sure if it was 93,94 that I put in those fractions, good job , by the way for the last question how did you find a and b.

 

[Adahshan]

No, sequence question was 0.5 and 1.5.. and the rod fits and for probability it was 94/150 x 93/149. I Aced the paper

 

[Cozmo35d]

I wrote for LCM : 2 and for HCM : 3 .
I hope it's right.

 

[Dooouuu]

No, sequence question was 0.5 and 1.5.. and the rod fits and for probability it was 94/150 x 93/149. I Aced the paper

yeah i did the sequence with the same answer

 

[Dooouuu]

I wrote for LCM : 2 and for HCM : 3 .
I hope it's right.

i did for lcm 2 also and the hcf 12 :S

 

[Ramosk95]

man wats ur variant bcz i have a different one??

 

[Ramosk95]

lcm is not 2
dooooouu, i solved these simultanuously and i put them in the original equation that the gave us and it was right for me for all the sequences
if u remember the equation write it down plz

 

[yousef0074]

an^3+bn^2+n , and for the last probability question i got 96/150 * 95/149

 

[Dooouuu]

lcm is not 2
dooooouu, i solved these simultanuously and i put them in the original equation that the gave us and it was right for me for all the sequences
if u remember the equation write it down plz

LOL ME TOO and gave me the appropriate answer ....something weird :S .. yeah and i know that i got the lcm answer wrong :S ...plz tell me what about the median interval ?

 

[Ramosk95]

so( -0.25*(1)^3)+(2.25*(1)^2)+1 all this should equal 3
now for the second one (-0.25*8)+(2.25*4)+2 should =9
these numbers 3 and 9 are given
lcm for 60 and 48 should equal to 240

 

[yousef0074]

guys, do you think there will be a range of answers for probability since values quoted from the graph may vary???

 

[Dooouuu]

ok what about .........0.5X2^3 + 1.5X2^2 + 2 = 12
and actually the total of the first 2 diagrams was 3+9 =12 !