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chem p12...hmm that was a tough one !!!

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Aloo007 said:
the compound was not CaC2H something it was with 4 carbons thats why i eliminated ethanoic acid as it only has two carbons

The question was talking about the empirical formula, if I remember correctly.
So 2 carbons would be possible.
 
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how if the empirical formulae is say CaC4H8 or something how can you get a compund with 2 carbons? minimum would be with 4
 
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yar
it is dioic
that means
tht
calcium will react with both Hydrogens from both of carboxilic groups
rite?
so hydrogen will be eleminated
and plus they said
excess of calcium
that means
react with both na
plus
then it forms
Ca2C4H4
which if u simplify as emperical formula
ull get CaC2H2
Ha now what
plus
which varient u take???
 
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the change in Chiral was +2 and -1.. since the secondary OH will be oxidised to =0 leaving the cholestrol with one less chiral.
 
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dude ur not making sense anyways i give up HAPPY! i did 12 BTW

@bilal but i was told KMn04 does not oxidize OH group :(
 
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look
this is what im saying
if calcium
is
ca2+
then it needs to replace 2 hydrogen group
form the acid
like
if suppose
Ca+2Hcl=CaCl2+H2
rite?
so normal butanoic acid has one cooh
which when calcium reacts it forms
Ca(C4H7O2)2
but in this case
one calcium
reacts with butan dioic
because it has two hydrogen
like
Ca+H2SO4=CaSO4+H2
Ca+C4H6O4=CaC4H4O4
so this is the emp[erical
formula
cuz calcium cant be sempelified
cuz its already 1
and third compund was the 2,methyle propandioic acid
so calcium gives
Ca(C4H4o4)
now if it is the answer
is C4 then it is A
man cuz calcium
reacts with Ch3-Cooh to form Ca(CH3COO)2
which gives CaC4H6O4
noow i maker sense or not????
 
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Nope.... KMnO4 is much stronger than K2cr2O7 so it does.. Its come in various past papers where they use KMnO4 in place of dichromate...
 
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Hateexams93 said:
EzioAuditre it was C , but i wrote A
If ur talking about the oxides of Nitrogen and Sulfur it was A.. If ur talking about the oxidation question and leaving bleach etc again it was A.
 
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Plx discuSS chEm P12..!! =)

heY ppl..plx discuss chem P12..discuss whtever questions u know..!! =)
 
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no bilal..the answer was tht precipitate one(i guess option c)..as the product had CL in it...the question was repeated..!! =)
 
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