CHEM P42 GT and paper discussion

[asenfire]

I have solvr this type of question before....see previous year papers

I solved from 02 to 13 but never found something like this where they specifically mentioned the solution or the electrolye is 'saturated'. Can you tell me the year??

 

[saadgujjar]

I solved from 02 to 13 but never found something like this where they specifically mentioned the solution or the electrolye is 'saturated'. Can you tell me the year??

wait by night

 

[asenfire]

wait by night

Okay i think i remember now. forget it, did this question contain 2 marks?

 

[saadgujjar]

Okay i think i remember now. forget it, did this question contain 2 marks?

yes one for tick and I don't know for explanation

 

[asenfire]

yes one for tick and I don't know for explanation

seems you will get 100 out of 100. How much did you get in As

 

[istudent]

Can anybody tell wht was final concentration of OH- in solution and final pH of solution

 

[itallion stallion]

as Pb2+ +2e---->Pb
in saturated solution concentration of Pb2+ will be low sio reaction will move backward,hence it will be more negative

U might be right.
As per the Eo of the equation u gave it is -0.13v when pb+2 concentration decreases reaction go backward as far ward is more negative going back will cause the Eo to become more positive although not zero volt option will be correct but the other option might be correct!

 

[Shehroze Faisal]

pH question please and electrolyte answer was -0.07

 

[Shehroze Faisal]

pH and conc of OH- ion

 

[A*(a*)]

in the NaOH and a weak acid qs we had to chose the last indicator na?
and did anyone get ph like 3.88 and 13.sth i guess?

 

[saadgujjar]

seems you will get 100 out of 100. How much did you get in As

inshallah 90+

 

[saadgujjar]

in the NaOH and a weak acid qs we had to chose the last indicator na?
and did anyone get ph like 3.88 and 13.sth i guess?

yeah 2.88

 

[ghulamhussain]

pH and conc of OH- ion

 

[A*(a*)]

yesss 2.88 and 13.sth is correct?

yeah 2.88

 

[asenfire]

yesss 2.88 and 13.sth is correct?

12.5

 

[A*(a*)]

yeah 2.88

what was the endpoint and any idea what were the marks in sketching the graph for apart from initial and final pH and end-point?

 

[A*(a*)]

12.5

maybe :/ I cant exactly commemorate. we knew the NaOH conc from which we calculated the OH conc, and used the Kw to calculate the H plus ions conc and then the PH of NaOH which is where the graph will end. Am I correct?

 

[Shehroze Faisal]

great 12.5 and 2.88

 

[Shehroze Faisal]

ki aey?

 

[asenfire]

maybe :/ I cant exactly commemorate. we knew the NaOH conc from which we calculated the OH conc, and used the Kw to calculate the H plus ions conc and then the PH of NaOH which is where the graph will end. Am I correct?

you take the excess OH- ions left after reacting with the acid and then divide it by total volume of resulting solution which is 10+20 com3 to get the new concentration