Chemistry 42....how did it go?..expected GT

[sadman]

how about me i got 87% on november'11 AS module , 20 in p5 , and 85 in p4?

definitely an A*

 

[ying27kia]

fat soluble is attached to the hydrocarbon tails which make up the hydrophobic part of the molecule.

Does the question really mention fat soluble? I think the drugs will attatch to -OH

 

[MER]

Thank You! So in total I'm losing maximum 15 marks. For the liposome I gave C and then B. C for the hydrophillic and B for the hydrophobic.

 

[extremeranger]

what did u guyz get for the tests?
i dont remember all but i remember putting 2,4-DNPH somewhere and also Tollens' Reagent for differentiating between ketone and aldehyde

 

[MER]

It was 3 marks only calculation

btw there was only this 1 calculation question in that elctrochemistry part right? The only other one was the E cell value as far as I remember. The E cell one was easy fortunately.

 

[tasnim007]

Are you kidding me? The whole question was worth 10 marks probably... The reaction kinetics part was max 6 marks...

I AM NOT SURE but wasn't the order of reaction part 6 marks and mechanism's part 4 marks
if it wasn't then I lose less then 10 marks
someone verify

 

[Jasmine1204]

was so bad,...................wt about second que it was so irritating....

bad bad bad

 

[aaditya menon]

How many marks for the CO diagram question?

 

[MER]

How many marks for the CO diagram question?

1 mark only bro.

 

[MER]

soo cool, nice
how did u calculate for the enthalpy change of solution for MgCl2 ?!

I calculated it like: Enthalpy change of solution of MgCl2= Enthalpy change of formation of MgCl2 (aq)- Lattice enthalpy.
Enthalpy change of formation of MgCl2(aq) and Lattice enthalpy of MgCl2 was given in the data. I'm hoping this was the right method.

 

[histephenson007]

I calculated it like: Enthalpy change of solution of MgCl2= Enthalpy change of formation of MgCl2 (aq)- Lattice enthalpy.
Enthalpy change of formation of MgCl2(aq) and Lattice enthalpy of MgCl2 was given in the data. I'm hoping this was the right method.

I think its actually enthalpy formation of MgCl2 (g) - enthalpy formation of MgCl2 (s)