Chemistry 9701/P22

[AizaAnjum]

who is up fo phy 33 tomorrow? and who is up for biology on 18th? i have phy paper the next monday... nothing in between. i hope phy goes better

 

[Anonymousx3]

who is up fo phy 33 tomorrow? and who is up for biology on 18th? i have phy paper the next monday... nothing in between. i hope phy goes better

Yeah, biology on Wednesday, that should be easy.
And I don't take physics, yay!

 

[AizaAnjum]

no biology for meeeeeeeeeeee but yeah i havephysics =ssssssssssss

 

[BILALrox01]

Bond enthalpy +485Kj.. KC 2.25.. H202 made.. Finally the compound other than H2SO4 had to be spluble so CaSO4 is wrong.. Also transition metals form Complex compounds so i don't know if they will aloow.. But K2CO3 nd Na2CO3 confirmed .. Nything else anyone wants to Knw?? The paper was damned easy.

 

[AizaAnjum]

how is the kc 2.25 what were your values

 

[AizaAnjum]

do we get ecf on wrong values? =S

 

[BILALrox01]

since 0.4 moles of NaOH react with Ethanoic acid at 1:1 there are 0.04 moles of Ethanoic acid at equilibrium. since initial moles were 0.1..0.6 moles of water nd ester is present each.. 0.06^2/0.04^2

 

[AizaAnjum]

DUDE
0.04 out of 0.1 REACTED. you were soppuse to subtract them!

 

[AizaAnjum]

suppose*

 

[BILALrox01]

Use ur god damned mind.. 0.04 is less then 0.1 How can u use -.6?? :crazy:

 

[AizaAnjum]

equilibrium concentration is not the stuff that reacted its the stuff that is left at equilibrium

 

[AizaAnjum]

0.1 were total moles. 0.04 reacted.

 

[Hateexams93]

yea dude your wrong

 

[AizaAnjum]

me?? ="( i just hope we get an ecf on the stupid values =S It was a 4 mark question!

 

[Anonymousx3]

If 0.04 moles reacted, then 0.06 moles were left at equilibrium.
0.06 x 0.06 / 0.04 x 0.04 = 2.25
=/ I wrote 0.44

 

[AizaAnjum]

exactly =/

 

[Hateexams93]

i didn't even write it , so i don't care , hhhh i screwed the whole thing

 

[AizaAnjum]

if 0.04 react 0.06 of the reactants are left behind. kc=products/reactants not reactants/ products

 

[BILALrox01]

Plz remember the question. It said the Mixture was in equilibrium.. than it was titrated with NaOH. do u remember what your values of NaOH titration was. Mine was .045.. 0.005 react with HCl so 0.04 is left that means 0.04 reacts with NaOH.. Now this was Ethanoic acid left right . Do we agree till here??

 

[obsessedgenius]

The value of Kc was 2.25 or smthng not 0.44.( btw I wrote 0.44 )...as NaOH was 0.045 moles and 0.005 reacted with HCl. 0.04 reacted with Ethanoic Acid, meaning that 0.04 moles of Ethanoic Acid were there at equilibrium. So Both the reactants were of 0.04 and products at 0.06 concentration. 8) ..it just didn't click at that time. I wrote the opposite and got 0.44