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for Q9http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Chemistry%20(9701)/9701_s07_qp_1.pdf
Q no 9 10 12 13 14 16 18 20 22 26 34 37 39 n 40 pleasee
let X2=A
Y2=B
X2y=C
C^2/(A^2)*B=2
C^2=2*(A^2)*B
SQUARE ROOT BOTH SIDES WE GET
C=(2^0.5)*A*(B^0.5) anything raised to 0.5 means it is square rooted ok
now for equation 2 we have
A*(B^0.5)/C
PUT IN VALUE OF C
WE GET A*(B^0.5)/(2^0.5)*A*(B^0.5)
thus we get 1/(2^0.5) as required by question