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hassam said:A mixture containing 0.100 mol of CaCO3 and 0.100 mol of CaO are introduced
into an evacuated 0.01 m3 vessel. The vessel is heated to a constant
temperature of 385 K such that the equilibrium below is established.
CaCO3(s) CaO(s) + CO2(g)
The partial pressure of carbon dioxide at equilibrium is then found to be 0.220
atm.
What is the total mass of CaCO3 at equilibrium after an additional 0.300 atm of
carbon dioxide is pumped into the vessel?
A 0.530 g
B 10.0 g
C 12.5 g
D 19.5 g
meoooow said:hii, :Search:
i need help with these!
meoooow said:hii, :Search:
i need help with these!
meoooow said:4 Some bond energy values are listed below.
bond bond energy / kJ mol–1
C–H 410
C–Cl 340
Cl–Cl 244
Br–Br 193
These bond energy values relate to the following four reactions.
P Br2 → 2Br
Q 2Cl → Cl2
R CH3 + Cl → CH3Cl
S CH4 → CH3 + H
What is the order of enthalpy changes of these reactions from most negative to most positive?
A P → Q → R → S
B Q → R → S → P
C R → Q → P → S
D S → P → Q → R
i hope this is better!
meoooow said:4 Some bond energy values are listed below.
bond bond energy / kJ mol–1
C–H 410
C–Cl 340
Cl–Cl 244
Br–Br 193
These bond energy values relate to the following four reactions.
P Br2 → 2Br
Q 2Cl → Cl2
R CH3 + Cl → CH3Cl
S CH4 → CH3 + H
What is the order of enthalpy changes of these reactions from most negative to most positive?
A P → Q → R → S
B Q → R → S → P
C R → Q → P → S
D S → P → Q → R
i hope this is better!
kakarocks said:meoooow said:hii, :Search:
i need help with these!
For the enthalpy change one its -88Kj i.e option B because 38 - 214 = -176 and -176/2 = -88
For Oxidation numbers its D +4,-4 because in ammonium nitrate one n was in a state of -3 and one in a state of +5 and they both came to +1 so the -3 one changed by by +4 and +5 one changed by -4
meoooow said:5 Given the following enthalpy changes,
I2(g) + 3Cl2(g) → 2ICl3(s) ΔHo = –214 kJ mol–1
I2(s) → I2(g) ΔHo = +38 kJ mol–1
What is the standard enthalpy change of formation of iodine trichloride, ICl3(s)?
A +176 kJ mol–1
B –88 kJ mol–1
C –176 kJ mol–1
D –214 kJ mol–
i really need help with this!
sakibfaiyaz said:meoooow said:4 Some bond energy values are listed below.
bond bond energy / kJ mol–1
C–H 410
C–Cl 340
Cl–Cl 244
Br–Br 193
These bond energy values relate to the following four reactions.
P Br2 → 2Br
Q 2Cl → Cl2
R CH3 + Cl → CH3Cl
S CH4 → CH3 + H
What is the order of enthalpy changes of these reactions from most negative to most positive?
A P → Q → R → S
B Q → R → S → P
C R → Q → P → S
D S → P → Q → R
i hope this is better!
P has +193..(check the data booklet)
Q has -244 , it has to be exothermic as bonds are only being made
R has -340 KJ.....USE enthalpy change= energy taken in to break bonds- energy given out by bond formation
S has +410...
Now arrange them from most negative to most positive. You will get R<Q<P<S...
therefore C
kakarocks said:Read above please meoow i mean :S
meoooow said:kakarocks said:Read above please meoow i mean :S
yes i did, im sorry, i just joined so its taking me a while to get a hang of this!
find the empirical formula for Q 1 and u will gind value of Xmizmoody said:Q1. In leaded petrol dere is an additive composed of Pb,C and H only. This compound contains 29.7% carbon and 6.19% hydrogen by mass.
What is the value of x in the emperical formula PbC8Hx?
A.5 B.6 C.16 D.20
Q2. A household bleach contains NaClO, as its active ingredient. The conc of NaClO in the bleach can be determined by reacting a known amount with aqeous H2O2.
NaClO(aq) + H2O2(qa) ====> NaCl(aq) + O2(g) + H2O(l)
When 25.0 cm3 of bleach is treated with an excess of aqueous H202, 0.0350 mol of Oxygen gas is given off. What is the conc of NaClO in the bleach?
A. 8.75x10-4 mol dm-3
B. 0.700 mol dm-3
C.0.875 mol dm-3
D.1.40 mol dm-3
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