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Sorry, thatz my fault...its a kind of addictionsweetiepie said:@ histephenson007 bt u hav marked it as B okay
@ xHazeMx thanks 4 corecting mee......
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Sorry, thatz my fault...its a kind of addictionsweetiepie said:@ histephenson007 bt u hav marked it as B okay
@ xHazeMx thanks 4 corecting mee......
KCN(aq/alcoholic) is used only for nucleophilic substitution, there are no groups here to be substituted. but CHO can undergo nucleophilic addition thats why we r using HCN in the first step and then aqueous acid to hydrolys each of the CN groups tp COOHmeoooow said:24 Tartaric acid is present in some wines. It may be synthesised in the laboratory in two steps.
OHCCHO intermediate HO2CCH(OH)CH(OH)CO2H
step 1 step 2
tartaric acid
Which reagents could be used for this synthesis?
step 1 step 2
A HCl (aq) HCN(g)
B HCN, NaCN(aq/alcoholic) H2SO4(aq)
C H2SO4(aq) K2Cr2O7 / H2SO4(aq)
D KCN(aq/alcoholic) K2Cr2O7 / H2SO4(aq
I know its B, but i want to know why its not D!
can someone pleease explain?
xHazeMx said:KCN(aq/alcoholic) is used only for nucleophilic substitution, there are no groups here to be substituted. but CHO can undergo nucleophilic addition thats why we r using HCN in the first step and then aqueous acid to hydrolys each of the CN groups tp COOHmeoooow said:24 Tartaric acid is present in some wines. It may be synthesised in the laboratory in two steps.
OHCCHO intermediate HO2CCH(OH)CH(OH)CO2H
step 1 step 2
tartaric acid
Which reagents could be used for this synthesis?
step 1 step 2
A HCl (aq) HCN(g)
B HCN, NaCN(aq/alcoholic) H2SO4(aq)
C H2SO4(aq) K2Cr2O7 / H2SO4(aq)
D KCN(aq/alcoholic) K2Cr2O7 / H2SO4(aq
I know its B, but i want to know why its not D!
can someone pleease explain?
Please answer my question someone..ShootingStar said:Question!
Please explain
C2H5OH + CH3CO2H CH3CO2C2H5 + H2Osparten said:guyz plz...
10 The value of the equilibrium constant, Kc, for the reaction to form ethyl ethanoate from ethanol
and ethanoic acid is 4.0 at 60 °C.
C2H5OH + CH3CO2H CH3CO2C2H5 + H2O
When 1.0 mol of ethanol and 1.0 mol of ethanoic acid are allowed to reach equilibrium at 60 °C,
what is the number of moles of ethyl ethanoate formed?
A 1/3, b)2/3 c)1/4 ,d)3/4
ShootingStar said:Question!
Please explain
its a one-step job in the calculator, it can be solved in ur way alsohassam said:its nt a mathematics ppr that u resorted to use QUADRATIC formula.....just take the sqrt on both sides and it makes it hell simple
Meh, I've explained this question to many people at XPF like 100 times. -_- Answer is A, anyway.ideggkr said:hassam said:welll y it shud nt be B but A???
I think you've discussed this enough with Zishi..
Well
delta H = bonds broken - bonds formed
bonds broken : c-c in graphite (let it be x)
bonds formed : c-c in diamond (let it be y)
x-y = +3
so x is greater than y
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