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Chemistry MCQ thread...

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xHazeMx said:

ans is D.

Sn1 is undergone by tertiary haloalkane
Sn2 is undergone by primary and secondary haloalkanes

- Sn1 and Sn2 are reaction mechanism
- when tertiary undergo substitution, the halogen has to break off first before the new nucleophile can fit in
- so it's like one by one, break then form so it's Sn1
- when primary and secondary undergo substitution, before the halogen break, the nucleophile has already form a partial bond with the C
- so at the intermediate stage, C is bonded to 5 groups
- so it's call Sn2

ok?
 
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I know the answer is D, but is it a hard-and-fast rule that ONLY tertiary alkyl halides undergo Sn1? It's written on WIkipedia that normally secondary and tertiary undergo.. Can anyone explain this..?
 
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zISHii...come'on i posted a tuff one for u
 

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RafaySid said:
I know the answer is D, but is it a hard-and-fast rule that ONLY tertiary alkyl halides undergo Sn1? It's written on WIkipedia that normally secondary and tertiary undergo.. Can anyone explain this..?
I remember reading from a textbook that secondary undergo a mixture of Sn1 and Sn2 mechanism.
so...

primary ....... Sn2 mechanism
secondary ..... mixture of Sn1 & Sn2 mechanisms
tertiary ........ Sn1 mechanism
 
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sweetiepie said:
DOES ANYONE HAS PAPERS B4 2002 PLZZ IF U HAV CAN U SEND MEE......:(
There was a topic few days ago where someone posted papers of 2000, u can search for it in other topics... it will probably be a few pages after this thread.
 
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Xthegreat said:
xHazeMx said:

ans is D.

Sn1 is undergone by tertiary haloalkane
Sn2 is undergone by primary and secondary haloalkanes

- Sn1 and Sn2 are reaction mechanism
- when tertiary undergo substitution, the halogen has to break off first before the new nucleophile can fit in
- so it's like one by one, break then form so it's Sn1
- when primary and secondary undergo substitution, before the halogen break, the nucleophile has already form a partial bond with the C
- so at the intermediate stage, C is bonded to 5 groups
- so it's call Sn2

ok?

Ok, but isn't SN1 (tertiary) the one with the intermediate?
http://en.wikipedia.org/wiki/SN1_reaction
 
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Xthegreat said:
xHazeMx said:

ans is D.

Sn1 is undergone by tertiary haloalkane
Sn2 is undergone by primary and secondary haloalkanes

- Sn1 and Sn2 are reaction mechanism
- when tertiary undergo substitution, the halogen has to break off first before the new nucleophile can fit in
- so it's like one by one, break then form so it's Sn1
- when primary and secondary undergo substitution, before the halogen break, the nucleophile has already form a partial bond with the C
- so at the intermediate stage, C is bonded to 5 groups
- so it's call Sn2

ok?
Thanks alot ! i had some confusion in this part
 
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both Sn1 and Sn2 have intermediates
its just that the Sn2's intermediate is a very fast step such that it is often ignored.
 
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Xthegreat said:
both Sn1 and Sn2 have intermediates
its just that the Sn2's intermediate is a very fast step such that it is often ignored.

aha, so if they ask which one has intermediate steps (like in a 1,2,3 question) , is it yes for SN2??
 
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