Chemistry : P1 and P2 doubts only (Only AS allowed)

[Manobilly]

J

yeah though i say dilute hydrochloric acid and heat under reflux but i guess dil. sulphuric acid is right too

JazakAllah

 

[Manobilly]

No 1 still answered my other doubt :'(

 

[syed1995]

X --- > Y + 2Z ( i dont knw jow to show reversible sign)
Initiall: moles 2 0 0 ( x disociated by 20% ... 0.4 of x converted to product)
2-0.4 0.4 0.8 ( I got Y and Z by mole ratio.. if 0.4 reacts then it will produce 0.4Y and 0.8Z)

P (x) = 1.6/2.8 x Tp
P (y ) =0.4/2.8 x Tp Tp = Total Pressure
P(z) = 0.8/2.8 x Tp

Just plug the values in the equation

Kp = P(y ) x (P(z))^2/P(x) (P(z))^2 because coefficients become power

AH SWEET>. that clears it up ...

 

[MustafaMotani]

AH SWEET>. that clears it up ...

yar itna clear likha tha gaps ke sath .. post karnay kay badd saray gaps ghayab ..

 

[syed1995]

Test for Alkene (the Br2 water test) .. the condition would be in darkness yeah? and what'd be the product? di-bromoalkane? or bromo-alcohol?

what about Br2 in CCl4 .. it will be at room temperature and only di-bromoalkane as product yea?

 

[syed1995]

yar itna clear likha tha gaps ke sath .. post karnay kay badd saray gaps ghayab ..

YEA I HATE when that happens.. we need to use dashes instead it thinks we are spamming

 

[A star]

Test for Alkene (the Br2 water test) .. the condition would be in darkness yeah? and what'd be the product? di-bromoalkane? or bromo-alcohol?

what about Br2 in CCl4 .. it will be at room temperature and only di-bromoalkane as product yea?

first the condition is rtp not darkness formation formation willl be bromo alcohol but u might get away wiith using just bromo alkane

 

[A star]

yar itna clear likha tha gaps ke sath .. post karnay kay badd saray gaps ghayab ..

shit happens nuf said

 

[MustafaMotani]

No 1 still answered my other doubt :'(

what is it .. ?

 

[A star]

guys any thing u found difficult any question ?????? anything new???????

 

[syed1995]

guys can anyone write here the full equation of reaction od H2SO4 with hydrogen bromidee and iodide

H2SO4 + NaBr --> NaHSO4 + HBr

2HBr + H2SO4 --> Br2 + SO2 + 2H2O

8HI + H2SO4 --> 4I2 + H2S + 4H2O

 

[syed1995]

guys any thing u found difficult any question ?????? anything new???????

We will know tomorrow

 

[A star]

then it will be off ) 0.000 percent of value

 

[Manobilly]

what is it .. ?

I need full working for solving kc questions like m/j 2007 2 c

 

[MustafaMotani]

I need full working for solving kc questions like m/j 2007 2 c

can u post the link plese

 

[Manobilly]

Here u go

 

[syed1995]

Haloalkane + aq NaOH is a reaction to make alcohol.. but is there a reaction between Haloalkanes and Water to make alcohol when heated?

 

[Manobilly]

T

Haloalkane + aq NaOH is a reaction to make alcohol.. but is there a reaction between Haloalkanes and Water to make alcohol when heated?

That OH in water is not much effective,the OH is more effective in NaOH

 

[A star]

Haloalkane + aq NaOH is a reaction to make alcohol.. but is there a reaction between Haloalkanes and Water to make alcohol when heated?

dont we heat the reaction mixture with reflux

 

[syed1995]

Here u go

PRODUCTS^moles/REACTANTS^moles

[CH3CO2C2H5][H2]/[CH3COOH][C2H5OH]

Kc = 4
Initial
Reactants=moles Ethanol=Ethanoic Acid = 0.5 moles
Products=moles of Water=Ester = 0.1 moles

Final would be
Reactants - x = ethanol-x , acid-x = (0.5-x) for both
Products +x = water+x,ester +x = 0.1+x for both

Now substitute that in the equation above...

(0.1+x)^2/(o.5-x)^2 = 4

take square root on both sides..

o.1+x/0.5-x = 2
0.1+x=1-2x
3x=0.9
x=0.3

Now calculate the no of moles.. by substituting x ..

Reactants = 0.5-x = 0.2 each
Products = 0.1+x = 0.4 each

Answer correct?