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Dude, wont it be "FeSO^4.xH2O" and we have to calculate x? Like in Nov09 p33hassam said:GUYX.....it ll be XSO4.7H2O
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Dude, wont it be "FeSO^4.xH2O" and we have to calculate x? Like in Nov09 p33hassam said:GUYX.....it ll be XSO4.7H2O
fireman said:Please tell me in DETAIL ,how do i find the value of X
filza94 said:Anyone please explain it in a simple, understandable way. Thanks.
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angelicsuccubus said:filza94 said:Anyone please explain it in a simple, understandable way. Thanks.
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hey .. which paper is this? what year?
Check paper Nov09 33zahraahmed said:hey i just had a look at the crucible experiments.
the crucible is used to convert a hydrated salt by heating into an anhydrous one......................now how does this fit here?
Feelguud77 said:Check paper Nov09 33zahraahmed said:hey i just had a look at the crucible experiments.
the crucible is used to convert a hydrated salt by heating into an anhydrous one......................now how does this fit here?
Method 1 of 2, its highly likely that something similar will come
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