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Chemistry P4| A2 only

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i sometimes feel like some questions in the inorganic part of section A are out of syllabus ? is this true or not
 
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Pleaseeeeeee guys can anyone tell me how do u balanceeee the equationnnn in Number 5 in N07 pleaseeee help guysssss i just cant balance the equation :(
 
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ok ...can nybody tell me wht do u mean by delocalisation of lone pair on pi bond of the benzene ring​
 
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i sometimes feel like some questions in the inorganic part of section A are out of syllabus ? is this true or not
they are not out of the syllabus .... itis just tht the equations are twisted up.....just to confuse us a little bit.....i feel tht tooo but if u try out the equations ull find it easy ...really u maight t ake a lill time to work over it...but ull succeed
 
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can any one pls help with the q
how is it 1st order with respect to H+.....
 

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how does an electron withdrawing or donating group.......affect acidity of a compound....
wht do these withdrawing and donating mean?
 
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Ecell = Ereduction-Eoxdiation right?

is it different if it is electrolysis? - then check w10 43 5b)... am i weird?
 
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EXACTLY. i"ve asked this question so many times. no one replied :(

It is easy.. from the first and second row, u can know that CH3CHO is 1st order.
From the first and third row , u can know that the run 1st order wrt CH3OH
From the first and fourth,

(0.2/0.2) x (0.16/0.1)x(0.1)(0.05) is 3.2, therefore it is also 1st order wrt H+
 
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It is easy.. from the first and second row, u can know that CH3CHO is 1st order.
From the first and third row , u can know that the run 1st order wrt CH3OH
From the first and fourth,

(0.2/0.2) x (0.16/0.1)x(0.1)(0.05) is 3.2, therefore it is also 1st order wrt H+
umm..i dont get it.. the way i do it is that we keep the conc of all other except the one whose order we are finding constant. why are you using .16/.1? :S
 
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Ecell = Ereduction-Eoxdiation right?

is it different if it is electrolysis? - then check w10 43 5b)... am i weird?

no Youre not weird..lol
In this case u calculate seeing the E0 valus of o2 and the cathode reaction theyve given!
If eo value is more positive for one u consider that to be undergoing reduction and the other to be undergoing oxidation..
In this case u cant assume reduction to occur at cathode..
 
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