chemistry p4 (order of reactions)

[bionology]

http://www.xtremepapers.me/CIE/Internat ... 8_qp_4.pdf

anyone please explain Q2 B,
how do we find order of reactions in these type of equations. I just understood some, but not all

 

[bionology]

beacon of light, or anyone please? Iam really stuck at it

 

[Astatine]

I'm assuming you don't understand the 2nd and last?
rate = k[H2O2]a[I–]b[H+]c

FOr step 2, IO- ion comes from H2O2 + I- and therefore in this case, H2O2 and I- each have a role in the rate equation; a = 1, b=1
c = 1 because the step is reaction with H+ ion.

For step 3, the HOI comes fro mstep which in turn comes from H2O2, I- and H+ ions. Till now, a =1, b=1 and c=1 {Got me so far?}

Since step 3 is a reaction with one more H+ and I-, c= 1+1 and b = 1+1
And hence a=1, b=2, and c=2

 

[zeebujha]

http://www.chemguide.co.uk/CIE/section8 ... i.html#top

Should solve your problem easily!