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Chemistry paper 1 doubts!!

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Oh i c .Thanx! Btw, how can we calculate for oxidation state..It is asked for in number 19 of this paper.
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Chemistry (0620)/0620_s08_qp_1.pdf
For e.g. Cr gives 6 electrons to oxygen in K2CrO4 so its oxidation state is Cr(-6)
While in K2CrO7 Cr gives 12 electrons so it state is (-12).
However in this question the products remain same that is why the oxidation state of the chromium ion remains same however due to the excess k2cro7 the ph increases
 
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because acid is added to alkaline solution so pH decreases. and secondly the precipitate forms with sulphuric acid not with hydrochloric acid so it precipitation reaction fails
 
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chlorination just purifies thw water from germs and bacteria. so only filtration would remove the excess fertilizers.
the 13th question is about electrolysis ,the ions in the solution are H+, Cl-, Na+and OH- so H+ discharges at the cathode
but Na+ is also present there so the colour of the indicator changes to purple. At the anode Cl- discharges so it bleaches damp
litmus paper (making it colourless) so D is rhe correct answer. Hope this helps
 
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