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Okay, seehttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w11_qp_41.pdf
Q 2(a)
Can somebody please tell me how to calculate the order with respect to H+??
Thank you very much.
Jazakum Allahu Khair!
Jazak Allahu Khair!Okay, see
We know that order of reaction of CH3CHO is one
so since it decrease from
0.25 to 0.2
so 0.25/0.2
=5/4
so basically the rate, must have decrease from 2 to 1.6 (2 x 4/5)
now we consider the change due to H is from 1.6 to to 3.2
and 3.2/1.6 is 2
and 0.1/0.05 is 2
so order is 1
0.25 -> 2Jazak Allahu Khair!
But how did you get 1.6?
Oh alright! Thanks a lot! Jazak Allahu Khair!!!!!!0.25 -> 2
0.2 -> x
x = 0.2 x 2 / 0.25
^this works since, they are proportional (order is 1)
or anyone online....please...
Right!! Jazak Allahu Khairan! Yes it has!If it is the one where you have to state the units of the rate constant, then:
The units of rate of reaction mol dm^-3 s^-1.
The reaction is first order with respect to each reactant involved, so to ensure that the units on the left of the equation are equal to the units on the right side,
mol dm^-3 s^-1 = k * (mol dm^-3)(mol dm^-3)(mol dm^-3)
Cancelling units from both sides,
s^-1 = k * (mol dm^-3)(mol dm^-3)
Rearranging for k,
mol^-2 dm^6 s^-1 = k
Therefore the units of the rate constant are mol^-2 dm^6 s^-1.
Hope this helped!
Good Luck for all your exams!
what about b(i) and (ii)??If it is the one where you have to state the units of the rate constant, then:
The units of rate of reaction mol dm^-3 s^-1.
The reaction is first order with respect to each reactant involved, so to ensure that the units on the left of the equation are equal to the units on the right side,
mol dm^-3 s^-1 = k * (mol dm^-3)(mol dm^-3)(mol dm^-3)
Cancelling units from both sides,
s^-1 = k * (mol dm^-3)(mol dm^-3)
Rearranging for k,
mol^-2 dm^6 s^-1 = k
Therefore the units of the rate constant are mol^-2 dm^6 s^-1.
Hope this helped!
Good Luck for all your exams!
Isn't it going to be a single carbon atom bonded to two Cl atoms? It will have a lone pair...what does the marking scheme say?http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s10_qp_41.pdf
Question 3 c (i)
Please, can anyone draw it?
well, check the mark scheme by replacing qp in link to msIsn't it going to be a single carbon atom bonded to two Cl atoms? It will have a lone pair...what does the marking scheme say?
Al7amdulillahwell, check the mark scheme by replacing qp in link to ms
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s10_ms_41.pdf
And yes..you are correct. Ma Sha Allah
Wa eyyakiAl7amdulillah
Thanks for the motivation
I was having such a bad day today....u just made me smile Jazak Allahu Khair!
http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_w11_qp_41.pdf could you do 2(b) (i) and (ii)??Al7amdulillah
Thanks for the motivation
I was having such a bad day today....u just made me smile Jazak Allahu Khair!
Look at the previous page PhyZac just explained it. if you still don't get it. Please feel free to ask, I'll be happy to helphttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w11_qp_41.pdf could you do 2(b) (i) and (ii)??
Actually I dint. He is asking a different question.Look at the previous page PhyZac just explained it. if you still don't get it. Please feel free to ask, I'll be happy to help
yep :|Actually I dint. He is asking a different question.
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