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Chemistry: Post your doubts here!

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from W10 please help with question 35,15,4
from S09 please help with 12,13,20
please explain to me.
 

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On collision, airbags in cars inflate rapidly due to the production of nitrogen.
The nitrogen is formed according to the following equations.
2NaN3 → 2Na + 3N2
10Na + 2KNO3 → K2O + 5Na2O + N2
How many moles of nitrogen gas are produced from 1 mol of sodium azide, NaN3?
A 1.5 B 1.6 C 3.2 D 4.0
 

Jaf

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^Yeah I still have a couple of hours in my exam. Fire away. I'll see what I can do.
 
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yessss:D
I2+3Cl2---->2ICl3 -214
I2(s)---->I2(g) +38
What is the standard enthalpy change of formation of iodine trichloride?
A +176
B -88
C -176
D -214
i cant get B
 
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which isomer forms 3 alkenes on dehydration?
A butan-1-ol
B butan-2-ol
C 2-methylpropan-1-ol
D 2-methylpropan-2-ol
its B bt i cnt get more than 2 alkenes.could u plz explain?
 
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0.2 mol of a hydrocarbon undergo complete combustion 2 give 35.2 g of carbondioxide and 14.4 g of water as the only products.
what is the molecular formula of the hydrocarbon?
A C2H4
B C2H6
C C4H4
D C4H8
its C but how:p
 
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ok i think the rescuer is no longer here...
plz help whoever comes and knows the answer :)
 

Jaf

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http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w05_qp_1.pdf

Can someone pleas help me with question 24? PLEASE? I really don't have any idea what to do.. PLEASE guys.
The answer is A. Try drawing all the possible alkenes that can be formed.
Butan-2-ol will form but-1-ene and cis but-2-ene and trans but-2-ene.
Propan-1-ol can only form propene.
2-methylbutan-2-ol can not be turned into an alkene as the hydroxy group is attached to a tertiary carbon.
2-methylpropan-2-ol can also not be turned into an alkene for the same reason as above.
 

Jaf

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yessss:D
I2+3Cl2---->2ICl3 -214
I2(s)---->I2(g) +38
What is the standard enthalpy change of formation of iodine trichloride?
A +176
B -88
C -176
D -214
i cant get B
You're missing important details of the question here. Please give the link of the original question.
 
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