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can u give me the link!!a member has answered this on one of the recent pages, you can see there
i cant find it!!
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can u give me the link!!a member has answered this on one of the recent pages, you can see there
a member has answered this on one of the recent pages, you can see there
exothermic-so should be decreasedWhen trying to increase the value of Kc for an exothermic reaction, should the temperature be increased or decreased? :/
how come 3 is correct, then??1 cant be right cuz when you heat under reflux with alkali the -Cl is going to be replaced by -OH, on acidifying dehydration will occur so no way a carboxylic acid is produced. if one is wrong the answer is C
When trying to increase the value of Kc for an exothermic reaction, should the temperature be increased or decreased? :/
Thank you so much! Life saver!N : P :K ratio
15:30:15
percentage nitrogen =(15/15+30+15) =0.25*100
25% of fertiliser;s mass is Nitrogen
reccommended usage is 14g
% of nitrogen in this =(25/100)*14
mass of nitrogen=3.5 g
no of moles =mass/Mr =3.5/14*2=0.125
concentration of N=0.125/5=0.025=0.03
can u plz explain how is the answer C!!Found it. I was right, the answer is C.
glad i could help ^^Thank you so much! Life saver!
how ?Found it. I was right, the answer is C.
It should be decreased.exothermic-so should be decreased
can u plz explain how is the answer C!!
how come 3 is correct, then??
help....anyone?http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w10_qp_11.pdf
Can anyone Please solve questions 5-10-12-21? pretty please ^^
Can you help me with my questions?glad i could help ^^
zone 4 ?=DThank you all so much for your help, I have my chemistry MCQs in about 8 hours so I'm going to head off to bed now. Best of luck to all of you, and I hope you get the best grades possible.
Remember to wish me luck in your hearts as well, as you all know, I'm going to need all the luck I can get. >_<
i'll try ^^Can you help me with my questions?
THANKYOU!!!!!!!!!!!!!!!!!!!!!!!! SOOO MUCH!!!!!!!!"the answer is C since the moles of CO2 produced=atoms of CO2:
1mol=24dm3thus 24000cm3
mols that occupy 72cm3=72/24000
moles that occupy72cm3=3*10^-3
so carbon atoms=3*10^-3
mass of this carbon atoms= 3*10^3*12(mr)
mass=.036g
mass of almunium=mass of compund-mass of carbon atoms
mass of almunium=.144-.036=.108
moles of Al=mass/Mr
moles=.108/27=4*10^-3
mole ratio of Al:C ------>4*106-3:3*10^-3
thus simple ratio is 4:3
so compound is Al4C3"
Original answer by Muhammad Asif, credit goes to him, not me.
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