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Chemistry: Post your doubts here!

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Omg thankyoooou!!
that helped a lot!! :')

for temperature its easier to learn just 1 variable lyk if rctn is exo,increacing temperature shifts equ. 2 da reactnats syd... if its endo, increasing temp shifts equ 2 da products syd and vice versa for decreasing temp
^^ could you please tell me why though? isnt exothermic bond formaton? so then why does it shft to the reactants side :/
no i dont think theres dis sort of explanation for dis...we just need 2 learn which syd is favoured by increasing or decreasing da temperature...btw i edited my post for concentration..plz chck :)
 
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u should ask in da A2 section
can ny1 tell me what are the important aspects or topics should i cover for the Bio-chemistry?
nd plz dont say me the syllabus just some of the most frequently asked sections!! pls
u mean da organic chemistry part ryt?? learn all da reactions and try solving as many pastpapers as u can..btw u shouldnt ask what 2 learn:p u cant leave any topic
 
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how did chem paper go for y'all ? it sucked for me . will proly get a C. :cry: . plz pray 4 me . tnx
 

Jaf

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Can this thread be locked and thrown away now that all the Chemistry exams are over? ^_^ Thanks.
 
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Can this thread be locked and thrown away now that all the Chemistry exams are over? ^_^ Thanks.
aoa wr wb!

we DID finish our chem exams, but the next batch is out there...they'll replace us :p
so no point in locking the thread :p
 
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plz help.
1.on heating,0.02 mol of the element M reacts with 0.025 mol of oxygen gas.what is the empirical formula of the oxide of M?
2.Br,extracted from dead sea,is transported as a 52%solution(by mass)of CaBr2.what mass of bromine,in tonnes,is contained in 100 tonnes of solution?(the use of data booklet is relevant)
3.when an evacuated glass bulb of 1 dm^3 capacity was filled with another sample of krypton at a pressure of 1 x 10^5pa and a temp of 300k,its mass increase by 3.32g.calculate the average Ar.
 
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For num. 1
You have already been given the number of moles of each component, simply divide by the smallest number, that is, M=(0.025/0.02) = 0.8 while with O2, u'll get 1. Multiply by 10 on each side to obtain whole numbers, ull get M8O10, simplify further u shall get M4O5, is that the answer?
For num 2, i got 41.6 tonnes but i'm not sure of the answer. if it is good, confirm with me and i'll post my workings.
Sorry I didn't have much time to complete with the other number today, maybe by the end of this week i shall give u the explanations. :)
 
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Hi.. I'm a newbie in A2.. This is is my today's homework.. I'm kinda lost in this question. Can anyone help??
The answer is 4.02 by the way. :)

Thanks in advance.

Screen shot 2012-07-04 at 9.14.00 PM.png
 
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Hi! Well i've got 4.01 as answer correct to 2 decimal places but i think is close enough. Here is the explanation:
C6H5COOH -> C6H5COO- + H+(ion)
1 mol of benzoic acid diss. to give 1 mole of benzoate and hydrogen ion
You have to find the [H+].

So, number of moles of benzoic acid from 0.25 moldm-3 = (30 x 0.25)/1000 = 7.5 x 10^-3 moles
and number of moles of NaOH which neutralised the acid = (20 x 0.15)/1000 = 3 x 10^-3 moles

The reaction of benzoic acid with NaOH is shown in the eqn:
C6H5COOH + NaOH -> C6H5COONa + H2O
from the eqn. 1 mol of benzoic acid reacts with one mole of NaOH, so, the number of moles of C6H5COOH which dissociated was 3 x 10^-3
hence, the number of moles of benzoic acid that remained in the solution was = 7.5 x 10^-3 - 3 x 10^-3 = 4.5 x 10^-3 moles

Plug ur values into the equation:
Ka = [C6H5COO-] x [H+] / [C6H5COOH]
6.4 x 10^-5 = (3x10^-3) [H+]/4.5 x 10^-3
[H+] = 9.75 x 10^-5

pH = -lg [H+] = -lg( 9.75 x 10^-5) = 4.02

Hope my answer has been helpful ;)
 
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Whats the equation for the reaction between calcium hydroxide and tartaric acid????????
please jaldo btao koi :p
 
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