- Messages
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where did u disappear ?
Sorry! Had to go out for something! I labelled X (mass of basic carbonate) and Y (mass of CuO)
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where did u disappear ?
alright see n= m/mr so for the basic carbonate nMr = m which is 1x (221+18x) and for the CuO m = 2 x 79.5 = 159Sorry! Had to go out for something! I labelled X (mass of basic carbonate) and Y (mass of CuO)
alright see n= m/mr so for the basic carbonate nMr = m which is 1x (221+18x) and for the CuO m = 2 x 79.5 = 159
now mass of basic carbonate/ mass of CuO i = gradient..substitute the values and find x. did u get it ? make sure u make a big triangle on ur graph when finding your gradient to make the answer as accurate as u can
no problemOHHHH GOT IT!!! Thanks! I just wasn't understanding how to use the gradient in it!!! Thank you!!!
alright see n= m/mr so for the basic carbonate nMr = m which is 1x (221+18x) and for the CuO m = 2 x 79.5 = 159
now mass of basic carbonate/ mass of CuO i = gradient..substitute the values and find x. did u get it ? make sure u make a big triangle on ur graph when finding your gradient to make the answer as accurate as u can
if a substance is oxidized then it is a reducing agent and if it is reduced then it is an oxidising agenthow to know if a substance is a reducing or oxidising agent. For example: how is CO a reducing agent.
i will need to read the whole question and do it and i am kind of busy now, i am sorry :/Could you help me with ON 2007 Q1 f also?? I don't understand the equation!!
Thanks..... Chem exam tomoro so i might disturb u the whole dayit is supposed to be +226
i will need to read the whole question and do it and i am kind of busy now, i am sorry :/
reducing agents are those ppl who like to reduce oxygens (Oxidation Guys)how to know if a substance is a reducing or oxidising agent. For example: how is CO a reducing agent.
ofc!! because the next coming days i will be doing paper 5 mostly and i will need u and all the other paper 5 candidates to discuss stuff about it and doubts like how yesterday we kept discussing. i guess this will help us to score a good grade, right ?Aww that's fine. Could you help me before Friday?
if its doubts about paper 2 you can disturb me the whole day !! its okay will do my best to answer your doubtsThanks..... Chem exam tomoro so i might disturb u the whole day
if you made your calculations above correctly then you will have 0.04 moles of NaOH that reacted with ethanoic acid which means at equilibrium we will have 0.1-0.04= 0.06 moles of ethanoic acid at equilibrium. acid to alcohol ratio is 1:1 so also 0.06 moles of alcohol left at equilibrium and 0+0.04 = 0.04 moles of water and sodium ethanoate al equil.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s11_qp_22.pdf
please someone help in 1(c)(i)
if its doubts about paper 2 you can disturb me the whole day !! its okay will do my best to answer your doubts
you mean what i said was wrong?if you made your calculations above correctly then you will have 0.04 moles of NaOH that reacted with ethanoic acid which means at equilibrium we will have 0.1-0.04= 0.06 moles of ethanoic acid at equilibrium. acid to alcohol ratio is 1:1 so also 0.06 moles of alcohol left at equilibrium and 0+0.04 = 0.04 moles of water and sodium ethanoate al equil.
THIS IS THE LOGICAL WAY. i don't know why the mark scheme made the opposite anyone out here can explain ??
oh what did u say ?you mean what i said was wrong?
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