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Chemistry: Post your doubts here!

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Someone Describe the use of lime in agriculture ?

cheated of wikipedia but these are quite a few uses :

The effects of agricultural lime on soil are:
  • it increases the pH of acidic soil (the higher the pH the less acidic the soil); in other words, soil acidity is reduced and alkalinity increased
  • it provides a source of calcium and magnesium for plants
  • it permits improved water penetration for acidic soils
  • it improves the uptake of major plant nutrients (nitrogen, phosphorus, and potassium) of plants growing on acid soils.
 
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cheated of wikipedia but these are quite a few uses :

The effects of agricultural lime on soil are:
  • it increases the pH of acidic soil (the higher the pH the less acidic the soil); in other words, soil acidity is reduced and alkalinity increased
  • it provides a source of calcium and magnesium for plants
  • it permits improved water penetration for acidic soils
  • it improves the uptake of major plant nutrients (nitrogen, phosphorus, and potassium) of plants growing on acid soils.
Thanks :D
 
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H-F----------------------- ▲Hf = -271 Kjmol-1
H-Cl---------------------- ▲Hf = -92 Kjmol-1
H-Br---------------------- ▲Hf= -36 Kjmol-1
H-I------------------------ ▲Hf = +26.5 Kjmol-1

So the bond enthalpy for HCL is +431 HBr is +366 and HI is +299 which is a given data.
Hydrogen halides formed are all simple molecular compounds which are gaseous at room temp. As the size oh the Hydrogen atom increases down the Gp, the H-X bond length also increase.Consequently, the H-X bond enthalpy decreases down the Gp.As you notice that the decrease in bond enthalpies means that the stabilities of the Hydrogen halides decrease down the group. HCl is stable at 1500 degrees, HBR decomposes at 800 decrease and HI decomposes at 500 thus HI is least stable of these three Hydrogen halides.

I've given a try :p

How can the size of the hydrogen atom increase down the group? It is the H-X bond which increases down the group as atomic radius of the halogen atom increases.
I agree that the H-X bond gets weaker as you go down Group VII and so accounting for the decreasing bond energies. What about the enthalpy of formation of H-X?
Enthalpy of formation: the heat change that occurs when 1 mole of H-X is formed from its elements at std conditions. Hey, thanks for helping me. ;)
 
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Can anyone help me how to find angles??
You have to consider the valence shell electron pair repulsion theory.
  • The theory gives the following order of repulsion of electron pairs: Lone pair/ lone pair > lone pair/bond pair > bond pair/ bond pair
From this you can deduce the shape and hence the angle.
Hope my answer has been helpful to you. :)
 
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Can anyone help me how to find angles??

an addition to what Amy Bloom has said. Draw the compound identify the no. of bond pairs and lone pairs on the central atom of your bond. If:
4 bond pairs only: 109.5 >tetrahedral
3 bond pairs and 1 lone pair: 107 > triangular pyramidal
2 bond pairs and 2 lone pairs: 104.5 >V-shape
3 bond pairs only: 120 >triagonal planar
2 bond pairs only: 180 >linear
6 bond pairs only: 90 >octahedral

the arrow follows the type of structure. good luck with these!
 
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an addition to what Amy Bloom has said. Draw the compound identify the no. of bond pairs and lone pairs on the central atom of your bond. If:
4 bond pairs only: 109.5 >tetrahedral
3 bond pairs and 1 lone pair: 107 > triangular pyramidal
2 bond pairs and 2 lone pairs: 104.5 >V-shape
3 bond pairs only: 120 >triagonal planar
2 bond pairs only: 180 >linear
6 bond pairs only: 90 >octahedral

the arrow follows the type of structure. good luck with these!
Maybe i can add something to this:
2 bond pairs and 3 lone pairs: Square based bi-pyramidal, but i don't know exactly the angle. You can see that in SF4. I've got this as a test.
 
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How can the size of the hydrogen atom increase down the group? It is the H-X bond which increases down the group as atomic radius of the halogen atom increases.
I agree that the H-X bond gets weaker as you go down Group VII and so accounting for the decreasing bond energies. What about the enthalpy of formation of H-X?
Enthalpy of formation: the heat change that occurs when 1 mole of H-X is formed from its elements at std conditions.

Yea i meant the size of the HALOGEN atom increases down the Group. The formation part would be helpful from someone else nw :p
 
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Aww.. thank you :D So how is your chemistry going ? Paper1 ? :eek:
Chemistry..... I don't know for now, for i haven't completed the syllabus yet & hv not worked out any past papers coz i'm appearing for November. Still do you have doubts?
 
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Guys is the application booklet extensive enough to rely upon and can we study only from there or should we buy another book also for application part of p4
 
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Maybe i can add something to this:
2 bond pairs and 3 lone pairs: Square based bi-pyramidal, but i don't know exactly the angle. You can see that in SF4. I've got this as a test.
isnt SF4 trigonal bi-pyramidal ? SF6 is octahedral or square bipyramidal or for that any 5 bonding pair and 1 lone pair, 4 bonding pair and 2 lone pair will be square bipyramidal.
 
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isnt SF4 trigonal bi-pyramidal ? SF6 is octahedral or square bipyramidal or for that any 5 bonding pair and 1 lone pair, 4 bonding pair and 2 lone pair will be square bipyramidal.
No. SF4's got 4 S-F bonds. So, it's gonna be "square" at the "base". Plus you've got 2 lone pairs at the top. If you consider the valence shell electron pair theory (lonepair/lonepair > lonepair/bond pair> bond pair/bond pair), the 2 lone pairs on top will repel other bonded pairs and hence the shape's going to be like a pyramid, but square based. Got it?;)
 
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No. SF4's got 4 S-F bonds. So, it's gonna be "square" at the "base". Plus you've got 2 lone pairs at the top. If you consider the valence shell electron pair theory (lonepair/lonepair > lonepair/bond pair> bond pair/bond pair), the 2 lone pairs on top will repel other bonded pairs and hence the shape's going to be like a pyramid, but square based. Got it?;)
Yeaa point ! thanks :)
 
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