- Messages
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- Reaction score
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- Points
- 73
To W07 Q9, is the answer B?
This is a redox reaction, with the sulphite oxidised to sulphate. Oxidation and reduction always come together. With sulphur oxidised, the "metal" must be reduced. You can see the change in oxidation number of sulphur is plus 2 (from +4 to +6). So if 1 mole of "metal" reacts with 1 mole of sulphite, the "metal" should experience a change of minus 2 in its oxidation number in order to compensate the oxidation. In this case, according to the volumes and molar concentrations, the mole ratio of "metal" to sulphite is 2 : 1, so the "metal" is reduced by only 1 oxidation number, so it's from +3 to +2.
W07 Q36,
1 should not be correct. The reaction must happen since sulphuric acid is acidic and potassium iodide is basic.
2 is correct since concentrated sulphuric acid is a strong oxidising agent, and iodide ion is a fairly good reducing agent, the redox reaction shall take place.
3... I cannot be sure, but that 1 is wrong and 2 is correct shall make you able to deduce that the answer is C.
Thanks can you explain the rest too?