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How to differentiate between addition and condensation polymer?
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prganic inorganic physical electro and applicationsAny important topics for tommorows p42???
amide/ester linkageHow to differentiate between addition and condensation polymer?
Amino Acid chains. C=O And N-H. Hydrogen bonds between O and N. And guess what! The O isn't directly attached to H!
You're very right here. Any other day, I'd have said you were right and Hydrogen Bonds exist b/w CH3F and H2O. BUT, not today. Not while you're still an A Level student. Not till you're done with P4 tomorrow. The A Level syllabus is limited to, rather stupidly, NOF bonded DIRECTLY to H with one exception of aa's in Applications. So, as far as questions go, you're not gonna use any logic. You're not gonna use your brain. You're going to see if N O or F is directly attached to H or not.
For R-COCl, Ar-Cl and RCl, which is easier to hydrolyse and why? I know Ar-Cl is the most difficult due to interaction between lone electron pairs of Cl and delocalised pi electrons of the benzene ring. But, what about the other two?
So R-COCl is easier to hydrolyse right?For R-COCl it is the easiest as the carbon atom attached to Cl is Extremely +ve beascause of the polar C--O bond and C--CL bond, both Cl and O are highly electronegative elements
For RCL only one electronegative element and there are no other interactions with it
So R-COCl is easier to hydrolyse right?
Thanks.
you wont ,trust me you have that feeling before an exam and you do good in it .I have the same feeling too.It's official. I'm screwed. I have forgotten everything. The one subject I had hopes of getting an A* in now see's me trying to just reach to an A, and even that seems like a huge task. FML.
Good luck, everyone!
hi, can any one tell me how to solve Q2/d/ii of 9701/42/0/n/09?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_qp_42.pdf
It's official. I'm screwed. I have forgotten everything. The one subject I had hopes of getting an A* in now see's me trying to just reach to an A, and even that seems like a huge task. FML.
Good luck, everyone!
Thanks but i still i cant understand it completely. does it have anything to do with such a high kc value? meaning that most of it(Ag+) has formed a complex?
Thanks but i still i cant understand it completely. does it have anything to do with such a high kc value? meaning that most of it(Ag+) has formed a complex?
yeah...........but. oh ok thenYou just assume that when you previously calculated the [Ag+], it is the same as the one you are using now. How else could you do it?
Do not worry! You are not alone ! Nah... just kidding, we will do fine! Usually the best chemists struggle the most, simply because they know the most!
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