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Chemistry: Post your doubts here!

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hey...can somebody help me out with dis...
its urgent...
7a i) General formula : CnH(2n+1) OH
Now for verifying it that this formula is correct or not let's take example ---> Ethanol which is two carbon alcohol so now put it into formula --> C2H([2*2]+1)OH ===> C2H5OH which means it is correct :)

ii) To find it's molecular formula we have to calculate emplerical formula mass --> CH3OH --> 12+3+16+1 => 32
Now, mass of 1 mole/emperical formula mass ====> 116/32 ---> 3.625 which is equal to 4
now multiply this number with emperical formula --> 4(CH3OH) ==> C4H7OH

Can you check this second one answer I am not sure fully
 
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7a i) General formula : CnH(2n+1) OH
Now for verifying it that this formula is correct or not let's take example ---> Ethanol which is two carbon alcohol so now put it into formula --> C2H([2*2]+1)OH ===> C2H5OH which means it is correct :)

ii) To find it's molecular formula we have to calculate emplerical formula mass --> CH3OH --> 12+3+16+1 => 32
Now, mass of 1 mole/emperical formula mass ====> 116/32 ---> 3.625 which is equal to 4
now multiply this number with emperical formula --> 4(CH3OH) ==> C4H7OH

Can you check this second one answer I am not sure fully
its not correct...
 
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im sorry Lucy Black i just started AS so im clueless :(
maybe ZaqZainab can help :)
Sorry for being late even though you( Lucy Black )got it
I will show you my way maybe it will be easier

ii) General formula of ALCOHOLS CnH(2n+1) OH, as magnanimous stated.
We know the ratio of masses C:H:OH will be 12n:1(2n+1):1*(16+1) from the general formula and they should equate to 116.
The 12,1 and (16+1) are the relative atomic masses
12n+2n+1+17=116
14n=98
n=98/14
n=7

Now just replace the n with 7 in the formula
C7H15OH
 
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