• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Chemistry: Post your doubts here!

Messages
15
Reaction score
10
Points
13
Right thankyou
btw can u tell me the difference in the reaction of benzene and methyl benzene with br2
The reaction with bromine

The reaction between benzene and bromine takes place with the help of a catalyst such as AlBr3 (if you are reacting with Cl2 then the catalyst will be AlCl3)
bromobenzene_equation.jpg


padding.gif
Methyl groups are 2,4-directing, which means that incoming groups will tend to go into the 2 or 4 positions on the ring.
bromine_reacts_with_aqueous_phenol.jpg

OH and CH3 are electron releasing (electron withdrawing) groups, this means that they are 2 ,4 directing group. As in the above diagram the Br2 is in excess so it will take all 3 positions : 2,4,6. If in limited quantity then it will occupy only 2 position.

See the Untitled.png which i have attached. Once you have gone through it you wont have any problem regarding positioning of atoms/molecules e.g Br2 etc

Hope this helps. :)(y)
 

Attachments

  • Untitled.png
    Untitled.png
    642.9 KB · Views: 10
Messages
2
Reaction score
0
Points
11

As we move across the period the ionization energy increses
So the top most peak is of group 8
And the lowest is of group 1 ( shown in the picture)

1 is correct b, j and r are group 8 as highest peak highest ionization across the period

2 is correct as d and l come after lowest peak (group 1) so they are in group 2

3 is correct as g and o are in group 5 and group 5 element have np3 configuration
Take eg of Nitrogen 1s2 2s2 3p3

Phosphorus. 1s2 2s2 2p6 3s2 3p3

P3 means half filled or unpaired electrons

Hope this helps
 

Attachments

  • PicsArt_1422867022990.jpg
    PicsArt_1422867022990.jpg
    134.1 KB · Views: 1
Messages
3,412
Reaction score
9,812
Points
523
But we don't have the bond energy of C-F? :/

Well, i guess you are supposed to know that C-F will have a comparatively higher bond energy as compared to C-Cl so you don't need to know it's bond energy.
Florine is more electronegative as compared to Chlorine and thus C-F bond is stronger as compared to C-Cl, thus requires more energy to break.
 
Messages
389
Reaction score
628
Points
103
Assalamu 3laikum! Firstly I'm really terrible at chemistry, so I've decided to take the exam in the O/N session.
Iz my decision ryt? I mean many of my school teachers say that the checking is strict in O/N session.
 
Messages
46
Reaction score
28
Points
28
I have tried this questions so many times but i am not getting a correct answer. please help.
may june 2014, component 12 Q # 9
 
Messages
254
Reaction score
413
Points
73
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w10_qp_12.pdf q8 ? And what's the general way of solving these kind of question where we have intermediates ?

The enthalphy change of formation hydrated calcium ions is this.
Ca(s) + aq – 2e– → Ca2+(aq)

So we need to go Ca2+ in the end.
We take Ca(s) and convert them to Ca(g) . Delta H = 177

Now comes the Data Booklet part.
We need to ionise this Ca(g).
First ionisation energy = 590
Second ionisation energy= 1150

Till now we have Ca 2+ (g)

We take that and convert to Ca2+ (aq) for which the energy is -1565.

Add all the energies. 177+590+1150-1565 = +352 which is (D)

In these questions just try to make connection and follow a route. Think about initial states and the final states and then solve it.
 
Top