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Halogenoalkanes in which all of the hydrogen atoms in the alkane have been replaced by halogen atoms are difficult to burn - hence their use in flame retardants and even in fire extinguishers.why is 2 incorrect ?
For which equation is the enthalpy change correctly described as an enthalpy change of formation?
A C(g) + O2(g) → CO2(g)
B C(s) + 0.5 O2(g) → CO(g)
C 2N(g) + 4O(g) → N2O4(g)
D 2NO(g) + O2(g) → 2NO2(g)
The answer is B...but why not A?
I kind of forgot the definition....anyways thanks a lot..I perfectly understoodFor enthalpy change of formation, the reactants have to be in their natural standard state
Carbon is given as a gas in A however it is found as a solid naturally, so it's B
Cream ppt is of Br- or Agbr while Yellow ppt is of I- or AgIWhy is it D... I thought it would be C because
- pale yellow ppt is formed by Br- when reacted with Silver nitrate
- white ppt for Cl-
- cream ppt for I-
and
- Cl- is soluble
- I- is soluble in concentrated ammonia
- Br- is insoluble
So if it is partly dissolved, and a darker yellow ppt is present, shouldn't Br- be present instead of I- because I- will also dissolve therefore there will be no ppt remaining after ammonia is added.....???
View attachment 51706
Shouldn't the electronic configuration be
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2
Since the 4s orbital is filled before the 3d orbital
But the mark scheme says
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 5s2
But i have been taught that 4s fills before 3d so which one is correct??
Can anyone please help me, I dont understand this question.
Thanks A Lot Mate15:30:15 is the ratio for N: P :K in 100g.
If the recommended usage is 14g of fertiliser, you need to change the ratios to match 14g.
15+30+15 = 60
NPK makes up 60g out of the 100g.
So how much will it make in 14g?
60/100 = x / 14
This gives you 8.4g out of the 14g.
15:30:15 is in the ratio 1:2:1, you need to split the NPK in this ratio.
You end up with 2.1 g / 4.2 g / 2.1 g
We're dealing with Nitrogen atoms, so we take 2.1 g and find the amount of moles present in 14g.
2.1g/14g = 0.15 mol
Now to find the concentration, we use the formula n = cV, where n is the number of moles, c is the concentration and V is the volume in dm^3.
n = 0.15
V = 5
c is what we're trying to find.
c = 0.15/5 = 0.03, hence your answer is A.
Hope that helped
Everything in the textbook is fruitful, you have the best notes in there.Hey guys where can i get simplest revision for As Chemistry..! P1 and P2
moles KOH = 1.0 x 10^-2 mol/dm^3 x 0.025 dm^3 =0.00025OK one more doubt..This one..
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