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Chemistry: Post your doubts here!

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Check out the attached question
The answer is A (1,2 and 3 are correct)
But V3+ means that it has 20 electrons
so that means it has a configuration of 1s2 2s2 2p6 3s2 3p6 4s2
this shows that all the orbitals are filled right?
Then how come it still has unpaired electrons?
 
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Why is it D... I thought it would be C because
- pale yellow ppt is formed by Br- when reacted with Silver nitrate
- white ppt for Cl-
- cream ppt for I-
and
- Cl- is soluble
- I- is soluble in concentrated ammonia
- Br- is insoluble

So if it is partly dissolved, and a darker yellow ppt is present, shouldn't Br- be present instead of I- because I- will also dissolve therefore there will be no ppt remaining after ammonia is added.....???
 

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Shouldn't the electronic configuration be
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2
Since the 4s orbital is filled before the 3d orbital
But the mark scheme says
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 5s2
But i have been taught that 4s fills before 3d so which one is correct??
 
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For which equation is the enthalpy change correctly described as an enthalpy change of formation?

A C(g) + O2(g) → CO2(g)

B C(s) + 0.5 O2(g) → CO(g)

C 2N(g) + 4O(g) → N2O4(g)

D 2NO(g) + O2(g) → 2NO2(g)

The answer is B...but why not A?
 
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For which equation is the enthalpy change correctly described as an enthalpy change of formation?

A C(g) + O2(g) → CO2(g)

B C(s) + 0.5 O2(g) → CO(g)

C 2N(g) + 4O(g) → N2O4(g)

D 2NO(g) + O2(g) → 2NO2(g)

The answer is B...but why not A?

For enthalpy change of formation, the reactants have to be in their natural standard state
Carbon is given as a gas in A however it is found as a solid naturally, so it's B
 
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For enthalpy change of formation, the reactants have to be in their natural standard state
Carbon is given as a gas in A however it is found as a solid naturally, so it's B
I kind of forgot the definition:oops:....anyways thanks a lot..I perfectly understood(y)(y)(y)(y)(y)
 
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Why is it D... I thought it would be C because
- pale yellow ppt is formed by Br- when reacted with Silver nitrate
- white ppt for Cl-
- cream ppt for I-
and
- Cl- is soluble
- I- is soluble in concentrated ammonia
- Br- is insoluble

So if it is partly dissolved, and a darker yellow ppt is present, shouldn't Br- be present instead of I- because I- will also dissolve therefore there will be no ppt remaining after ammonia is added.....???
Cream ppt is of Br- or Agbr while Yellow ppt is of I- or AgI
 
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View attachment 51706
Shouldn't the electronic configuration be
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2
Since the 4s orbital is filled before the 3d orbital
But the mark scheme says
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 5s2
But i have been taught that 4s fills before 3d so which one is correct??

yeah thats correct, its just that try to write the electronic configuration in the order.. even your way is acceptable, acc to my teacher.
 
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do all the organic chemistry reaction have only one kind of reaction path diagram ??????????
And can any one show it for me plzzzz
 
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Can anyone please help me, I dont understand this question.

15:30:15 is the ratio for N: P :K in 100g.
If the recommended usage is 14g of fertiliser, you need to change the ratios to match 14g.

15+30+15 = 60
NPK makes up 60g out of the 100g.
So how much will it make in 14g?
60/100 = x / 14

This gives you 8.4g out of the 14g.

15:30:15 is in the ratio 1:2:1, you need to split the NPK in this ratio.

You end up with 2.1 g / 4.2 g / 2.1 g

We're dealing with Nitrogen atoms, so we take 2.1 g and find the amount of moles present in 14g.
2.1g/14g = 0.15 mol

Now to find the concentration, we use the formula n = cV, where n is the number of moles, c is the concentration and V is the volume in dm^3.

n = 0.15
V = 5
c is what we're trying to find.

c = 0.15/5 = 0.03, hence your answer is A.

Hope that helped (y)
 
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15:30:15 is the ratio for N: P :K in 100g.
If the recommended usage is 14g of fertiliser, you need to change the ratios to match 14g.

15+30+15 = 60
NPK makes up 60g out of the 100g.
So how much will it make in 14g?
60/100 = x / 14

This gives you 8.4g out of the 14g.

15:30:15 is in the ratio 1:2:1, you need to split the NPK in this ratio.

You end up with 2.1 g / 4.2 g / 2.1 g

We're dealing with Nitrogen atoms, so we take 2.1 g and find the amount of moles present in 14g.
2.1g/14g = 0.15 mol

Now to find the concentration, we use the formula n = cV, where n is the number of moles, c is the concentration and V is the volume in dm^3.

n = 0.15
V = 5
c is what we're trying to find.

c = 0.15/5 = 0.03, hence your answer is A.

Hope that helped (y)
Thanks A Lot Mate :)
 
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