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http://www.chemguide.co.uk/organicprops/nitriles/hydrolysis.htmlcan someone tell me wht happens when a nitrile reacts with an acid?
The cynide ion gets replaced with wht?
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http://www.chemguide.co.uk/organicprops/nitriles/hydrolysis.htmlcan someone tell me wht happens when a nitrile reacts with an acid?
The cynide ion gets replaced with wht?
There are only 5 papers.Where can I find very good Chemistry paper 6B notes?
Please advise
thanks bro
thank uThis is hydrolysis of nitrile, catalysed by the acid. Simply replace the nitrile group with carboxlic acid group.
Eg:
CH3CN ---------(HCl(aq), heat under reflux) --------> CH3COOH
Hahahaha Atleast u triedwa alaykum salaam
Firstly, I'm so mad I concentrated so much on this and then realised it was A2 afterwards...
I haven't done A2 so I may be wrong but it seems like compound D has to be a carbonyl compound, and the functional group you've given is not a carbonyl compound.
In the question it says it reacts with 2,4-DNPHHahahaha Atleast u tried
Umm its actually some reaction of iodomethane in A2 part
Ok y are u saying it shud be carbonyl compound?
Oh my lord!In the question it says it reacts with 2,4-DNPH
Haha happens sometimesOh my lord!
idk wat the hell I hve been reading xP
Thankyew....I got it finally xD
Use Hess's Law and construct a cycleCan anyone explain this to me? Thank You.!
E. Change of formation of CO2= -395kjmol^-1
E. Change of formation of H2O= -297kimol^-1
E. Change of combustion of C2H6= -1620kJmol^-1
Calculate the enthalpy of the formation of ethane.
[-2(395)+3(-297)]-(-1620)
= -61kJmol^-1
WHY?
Can anyone explain this to me? Thank You.!
E. Change of formation of CO2= -395kjmol^-1
E. Change of formation of H2O= -297kimol^-1
E. Change of combustion of C2H6= -1620kJmol^-1
Calculate the enthalpy of the formation of ethane.
[-2(395)+3(-297)]-(-1620)
= -61kJmol^-1
WHY?
Reaction is ES so will require Cl2+AlCl3/FeCl3Asak ppl
can someone tell me in Q4 (d) for reaction 2, is heating necessary ?
http://onlineexamhelp.com/wp-content/uploads/2014/08/9701_s14_qp_42.pdf
yea thats wat my miss taught me but ms says heat :/Reaction is ES so will require Cl2+AlCl3/FeCl3
Well,isnt KMnO4 an oxidising agent?IT IS first and foremost,its the conditions that cause it to break the C=C,but along with that it will oxidise anything it can ,which include the OH and COH groups.HNE is a reactive compound.
CH3(CH2) 4CH(OH)CH=CHCHO
(c) Give the structural formulae of all of the carbon-containing compounds formed in each case when HNE is reacted separately with the following reagents.
(i) hot concentrated manganate(VII) ions in acid solution.
So what I came up with is: CH3(CH2)4CH(OH)CO2H + HO2CHO
but in the markscheme the OH- group and the CHO group have also been oxidised giving: CH3(CH2)4COCO2H and HO2CCO2H
What i don't get is that it says manganate ions, not dichromate, so how can the alcohol and the aldehyde group get oxidised as well?
Are you sure its Hot Conc K2Cr2O7 and not KMnO4?Q what will be the result of oxidising this compound with Hot conc K2cR2O7.
Acc to me there should be no change!! any help will be appreciated!
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