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According to me, its should be near 630 - 660. I got 630so A too. Wait for answer.is it A
Helpppp please!!!!!
is it B
The book has the answer sheet.Yes it is, how did you figure it out? :/
Vol of oxygen : 80cm^3when 20cm (cube) of a gaseous hydrocarbon were completely burnt in excess of oxygen, 60cm(cube) of carbon dioxide and 40cm(cube) of water vapour were formed, all volumes being measured at same temperature and pressure.
what is the formula of the hydrocarbon ?
A.C2H6
B.C3H4
C.C3H6
D.C3H8
ANS : B
how to work out this question ?
Thanks
Yes it is, how did you figure it out? :/
HOw you got volume of oxygen 80cm(cube)Vol of oxygen : 80cm^3
Hydrocarbon + O2 --------> CO2 + H2O
Set ratio.
1Hydrocaron + 4O2 ---> 3CO2 + 2H2O
You can see there are 3 carbon and 4 hydrogen hence C3H4
All volumes being measured at same temperature and pressure.HOw you got volume of oxygen 80cm(cube)
is there any kind of formula you used ?
Initial moles H2O = 1help please
FOR 11 - In D see the forces are getting stronger as it goes frm liquid to solid but in case of C we need to break the forces in solid to form liquid...So in C we need to overcome the forces.http://www.sheir.org/a-level-chemistry-11-june2011.pdf
Question 8?
And in 11 why's D wrong?
13 My answer's D. What did I do wrong in this calculation:
Al2O3: 6HCL
0.02x6= 2xvolume/1000
AND I DONT GET 15 AND 16 AT ALL!
Q13- 4Al + 3O2 ---> 2AlO3http://www.sheir.org/a-level-chemistry-11-june2011.pdf
Question 8?
And in 11 why's D wrong?
13 My answer's D. What did I do wrong in this calculation:
Al2O3: 6HCL
0.02x6= 2xvolume/1000
AND I DONT GET 15 AND 16 AT ALL!
But why don't you take the moles of Al2O3 to that of HCl directly?Q13- 4Al + 3O2 ---> 2AlO3
Al2O3 + 6HCl ----> 2AlCl3 + 3H2O
Ratio of Al : Al2O3
4 = 2
0.02 = ?
=0.01 moles of Al2O3
now ratio of Al2O3 : HCl
1 = 6
0.01 = ?
=0.06
use the formula no.of moles = vol x conc. to find the volume
that will be 0.06/2 = 0.03 dm3
is the moles given in the question ?But why don't you take the moles of Al2O3 to that of HCl directly?
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