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Chemistry: Post your doubts here!

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So we have an upcoming chemistry MCQ exam and i keep getting MCQs for organic chemistry wrong :(
any advice?
Thanks
 
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Initial moles H2O = 1
Initial moles CO = 1
Eq moles H2O = 1-x
Eq moles CO = 1-x
Eq moles H2 = x
Eq moles CO2 = x

Total moles = (1-x) + (1-x) + x + x = 2
if hydrogen occupies 33% = 2/3 moles hence CO2 is also 2/3 moles and CO and H2O have 1/3 moles

Now put the values into the equilibrium law.
but my answer comes wrong if I do it this way :(
I have the solution for this question with the correct ans but
I don't get why we have to multiply moles of H2 by 2
 
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You are referring to the line

mole of H2 formed = 33.3/100 *2 ?

The 2 is the total moles of gases, moles of H2 = % of H2 x total moles
 
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Leaving mathematical calculations aside, we can reason it out in this manner.

A <-> B exothermic can also be represented by A <-> B + heat

A <-> B endothermic can also be represented by A + heat <-> B

Changing the temperature (removing or adding heat) will shift the equilibriums above.

Only equilibriums that are neither exothermic nor endothermic will not shift during temperature changes.
In other words, the enthalpy change of such reactions is zero (heat is neither a "reactant" nor a "product".)
 
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In aqueous solution, the acid HIO disproportionates according to the following equation where m,
n, p and q are simple whole numbers in their lowest ratios.
mHIO → nI2 + pHIO3 + qH2O
This equation can be balanced using oxidation numbers.
What are the values for n and p?
n p
a) 1 2
b) 2 1
c) 4 1
d) 4 2


the answer is B
I know how to figure out the oxidation numbers, but I need explanation on how to balance such equations using oxidation numbers... help please!!
 
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