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http://www.sheir.org/a-level-chemistry-13-nov2010.pdf
Question 25 why not A??
And in 12 my ans is A?
Question 25 why not A??
And in 12 my ans is A?
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I end up with 6 :s![]()
http://www.sheir.org/a-level-chemistry-13-nov2010.pdf
Question 25 why not A??
And in 12 my ans is A?
what are the intermediates for each?
its correctThats the wrong answer? Which year is it?
View attachment 54141
Doesn't Selenium also have 6 unpaired electrons??
So does chromium ... B is correct but then what about D?
why is barium sulphate not soluble in the acid? ://barium sulphate in hydrochloric acid shud form barium chloride which is soluble ,no???Q16. Barium sulfate is not soluble in the acid, whereas barium carbonates reacts with the acid to form a soluble barium compound.
Q26. X represents a halogen atom.
W: CH3CH2XCH3
X: CH3CH(OH)CH3X
Y: CH3CH2XCH3
Z: CH3CH2CH2OH
Q16. Barium sulfate is not soluble in the acid, whereas barium carbonates reacts with the acid to form a soluble barium compound.
Can you type out the spdf configurations of the mentioned atoms?
What values are you using? Chances are you didn't convert dm3 to m3.
why is barium sulphate not soluble in the acid? ://barium in acid shud form barium chloride which is soluble ,no???
Oh you have to use spdf!? Selenium is in group 6 which shows it's short of 2 electrons right? so i just assumed that means it has 6 unpaired electrons
Ok so by using spdf it shows that selenium doesn't have unpaired electrons
And for the second Q
I'm using these values
pv = nRT
(1 x 10^5) x (1.247 x 10^-1) = (6.35 / 253.8 ) x 8.31 x T
so T = 60000K
So what values are wrong??
Oh i see! i just divided by 10 from deci to meter ... didn't cube it!volume needs to be converted to m3.
solubility rules, BaSO4 is insoluble.
Hmm.. Which reaction are you basing on when you mention barium sulfate and acid?
Solubility rules apply to all solvents? be it acid, base etc? :Osolubility rules, BaSO4 is insoluble.
Hmm.. Which reaction are you basing on when you mention barium sulfate and acid?
Solubility rules apply to all solvents? be it acid, base etc? :O
Draw the isomers that you have, likely you have 2 of the same kinds.
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