- Messages
- 26
- Reaction score
- 10
- Points
- 13
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This question is pretty easy. 2EN (Cl) are in diagonals which cancels each other out, in no other option there u see EN elements in diagonal hence DView attachment 54156
I never understood how to know which one has more/less overall dipole. Can anyone explain this to me? The answer is D
View attachment 54156
I never understood how to know which one has more/less overall dipole. Can anyone explain this to me? The answer is D
Arent the Cl atoms in option B also pulling in opposite directions? or does that count as the same direction?The Cl atoms are electronegative, look for the symmetry, D has the Cl pulling the electrons in opposite directions and canceling each other out.
It should be in diagonals. In B overall DPM is +---->Arent the Cl atoms in option B also pulling in opposite directions? or does that count as the same direction?
Arent the Cl atoms in option B also pulling in opposite directions? or does that count as the same direction?
You can try to create the 2 half equations
2HIO + 2H+ + 2e- --> I2 + 2H2O ------ (1)
HIO -+ 2H2O -> HIO3 + 4H+ + 4e- ------ (2)
Before combining the 2 equations, we need to make both equations have the same number of electrons
(2) x 2 + (1)
So ratio of I2 to HIO3 is 2: 1
thanks loadz!Oxidation state of I in HIO, I2 and HIO3 is +1, 0 and +5 respectively.
Oxidation change from HIO to I2 is -2 (not -1 coz I-I)
Oxidation change from HIO to HIO3 is +4
View attachment 54137
Interchange the numbers, ie 2 for HIO3 and 4 for I2
2 : 4 ----> 1 : 2
n = 2 p = 1
i will tell u wat i thinkHow is this possible? :/
How can we know if the fwd rate is increase or not by the shifting of eq to fwd direction?i will tell u wat i think
they are asking abt RATE ryt?
removing ammonia will shift the equilibrium towards the forward reaction but rate wont increase i guess
check the rest of the options - all are the factors which affects the rate nd will definitely increase the rate of reaction
rate is like speed of the reaction and that is related to collisions nd all
ok till now i had the same problem like u....i used to be like its favoring forward reaction so rate of the reaction will be highHow can we know if the fwd rate is increase or not by the shifting of eq to fwd direction?
Check out C - My confusion.
Thanks.ok till now i had the same problem like u....i used to be like its favoring forward reaction so rate of the reaction will be high
but most of the questions are just related to the factors which affect the rate
C- at first i wud say its wrong but see increasing temperature increases the kinetic energy of the molecules so more effective collisions which increases the rate of the reaction
removing ammonia will shift the equilibrium forward nd we will get more amount of ammonia but nothing will happen to rate...this is wat i understood :/
i will tell u wat i think
they are asking abt RATE ryt?
removing ammonia will shift the equilibrium towards the forward reaction but rate wont increase i guess
check the rest of the options - all are the factors which affects the rate nd will definitely increase the rate of reaction
rate is like speed of the reaction and that is related to collisions nd all
write the whole reaction nd seePLEASEEEE HELPPPPPPP
CORRECT ANSWER IS C.
Pressure and temperature increase the rate of BOTH backward and forward reaction, its just that either the forward or backward is increased by a higher amount. In the case of haber process higher temp increases the backward reaction MORE than it increases the forward reaction, hence it shifts to the left hand side, but in general an increase in pressure/temp increases both forward and backward reaction.How is this possible? :/
concentration too yea?Pressure and temperature increase the rate of BOTH backward and forward reaction, its just that either the forward or backward is increased by a higher amount. In the case of haber process higher temp increases the backward reaction MORE than it increases the forward reaction, hence it shifts to the left hand side, but in general an increase in pressure/temp increases both forward and backward reaction.
what is the answer?How do we solve this?!!
Two glass vessels M and N are connected by a closed valve.
M contains helium at 20 °C at a pressure of 1 x 10^5 Pa. N has been evacuated, and has three times the volume of M. In an experiment, the valve is opened and the temperature of the whole apparatus is raised to 100 °C.
What is the final pressure in the system?
a. 3.18 x 10^4 Pa
b. 4.24 x 10^4 Pa
c.1.25 x 10^5 Pa
d.5.09 x 10^5 Pa
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