Chemistry: Post your doubts here!

[Studydayandnight]

what is the answer?

It's A.

 

[Studydayandnight]

PLEASE HELPPPPPPPPPP

Correct answer is B.

 

[Studydayandnight]

How do we figure out the number of chiral centres present??
Correct answer is 6.

 

[Studydayandnight]

Omg, wth is this? -_-

Correct answer is D.

 

[lara dalal]

It's A.

Here is what I did, Idont know if there is another way of solving it or not. Anyhow this is how i did it.
First I found the volume of M in terms of n using PV=nRT (there is no way of actually finding the number of moles because they didnt give you the mass of Helium or its volume) Anyhow
Volume of M --> 1x10^5*V=n*8.31*(20+273)
V=0.024n
Now they told you that the volume of N is three times that of M hence Vol of N is 3*V i.e 3*0.024n = 0.073n
Now they asked for the final pressure which means the pressure of both the gasses M and N and they told you that the temp is 100 so what we do is first we find the TOTAL volume of both M and N which is 0.024n+0.073n= 0.097n
so to find the Total pressure just put in your values in the formula
P*0.097n=n*8.31*(100+273) (the n will cancel out)
P=3.18x10^4
BTW when you attempt solving it yourself use the exact values from the calculator, if you use my rounded off values you will get 3.19x10^4

 

[lara dalal]

PLEASE HELPPPPPPPPPP

Correct answer is B.

use m*c*delta T using m as your mass of water (because that is what is actually absorbing the heat)
200*4.18*(55-25)=25080J
Now convert that to KJ by dividing 25080 by 1000= 25.08KJ
To convert it to KJ/mol divide the 25.08 by the number of moles of the fuel used that is.0326
25.08/.0326=769

 

[cirron]

can any kind soul clear my doubts
here are the answers
1.C
7.C
10.A
12.D
14.B
25.C

 

[qwertypoiu]

How do we figure out the number of chiral centres present??
Correct answer is 6.

I spot 7

 

[Metanoia]

How do we solve this?!!

Two glass vessels M and N are connected by a closed valve.

M contains helium at 20 °C at a pressure of 1 x 10^5 Pa. N has been evacuated, and has three times the volume of M. In an experiment, the valve is opened and the temperature of the whole apparatus is raised to 100 °C.

What is the final pressure in the system?

a. 3.18 x 10^4 Pa
b. 4.24 x 10^4 Pa
c.1.25 x 10^5 Pa
d.5.09 x 10^5 Pa

Here is what I did, Idont know if there is another way of solving it or not. Anyhow this is how i did it.
First I found the volume of M in terms of n using PV=nRT (there is no way of actually finding the number of moles because they didnt give you the mass of Helium or its volume) Anyhow
Volume of M --> 1x10^5*V=n*8.31*(20+273)
V=0.024n
Now they told you that the volume of N is three times that of M hence Vol of N is 3*V i.e 3*0.024n = 0.073n
Now they asked for the final pressure which means the pressure of both the gasses M and N and they told you that the temp is 100 so what we do is first we find the TOTAL volume of both M and N which is 0.024n+0.073n= 0.097n
so to find the Total pressure just put in your values in the formula
P*0.097n=n*8.31*(100+273) (the n will cancel out)
P=3.18x10^4
BTW when you attempt solving it yourself use the exact values from the calculator, if you use my rounded off values you will get 3.19x10^4

It is not necessary to find the number of moles (which are the same in the beginning and the end).

 

[Metanoia]

can any kind soul clear my doubts
here are the answers
1.C
7.C
10.A
12.D
14.B
25.C

Q1. Form a balance equation for the reaction.

Pb4+ + 2Br- --> Pb2+ + Br2

Moles of Pb4+ = 6.980/Mr of PbCl4
Work towards moles of Br2.....

Q7.


2 moles of NF3 are broken down into its atoms, so 6 moles of N-F bonds are broken.

Each N-F requires = + 1668/6 kJ of energy (positive as it is endothermic)


Q12.


Q14.
Group II nitrates decompose based on the equation below:

2 X(NO3)2 (s) --> 2 XO (s) + 4 NO2 (g) +O2(g)

Mass of XO = 5 -3.29 g = 1.52
Moles of XO = 1.52/ (Mr of X + 16)

Mass of X(NO3)2 = 5 g
Moles of X(NO3)2 = 5/(Mr of X + 124)

since moles of X(NO3)2 = moles of XO
5/(Mr of X + 124) = 1.52/ (Mr of X + 16)

We can solve for Mr of X using the equation , or you can substitute the Mr of the four options and do trial and error.

Q25.
75% of ethanol was converted = 0.75 x 2.76 = 2.07 g

ethanol --> ethanal
C2H5OH --> C2H4O

Moles of ethanol converted =?
Moles of ethanal formed =?
Mass of ethanal formed = ...

 

[princess Anu]

why is it 1:3 & not 1:1

 

[Farhad221]

The answer is C but shouldn't it be A.

 

[Farhad221]

The correct answers are A and B respectively. The second question is from section B hence 1 and 2 are correct. Can someone explain to me why?

 

[Farhad221]

why is it 1:3 & not 1:1

First of all the reaction is hemolytic fission. Then if we draw out the propogation and termination steps of reaction you can see if the chlorine atom joins at first or second carbon atom we get 1-chloropropane whereas we only get 2-chloropopane if it joins at second carbon atom. Hydrogen atoms at 2nd carbon are two and 1st and 3rd carbon are 6. the ratio will be 3:1

 

[The Sarcastic Retard]

The answer is C but shouldn't it be A.

x = 104.5
y = 109.5
z = 107.5
y -> z -> x

 

[Farhad221]

x = 104.5
y = 109.5
z = 107.5
y -> z -> x

why is x 104.5 shouldnt it be 180

 

[The Sarcastic Retard]

can any kind soul clear my doubts
here are the answers
1.C
7.C
10.A
12.D
14.B
25.C

10)
A) HSO3 is a proton acceptor. Proton acceptor is a base.
B) SO2 is a reductant.
C) 2H+ donated proton to SO3(-2). Hence its base.
D) SO3(-2) is an oxidant.

 

[The Sarcastic Retard]

why is x 104.5 shouldnt it be 180

There are two lone pairs. H-O-H isnt 180 coz of lone pair, CO2 is pure sp hybridization without lone pair, hence its linear.

 

[The Sarcastic Retard]

PLEASE HELPPPPPPPPPP

Correct answer is B.

Energy = 200 * 4.18 * 30 = 25080J
0.0326mol ---> 25080J
1mol ----> ?
25080/0.0326 = 769325.1534 = 769 kJ/mol (Combustion is exothermic reaxn) = -769kJ/mol

 

[princess Anu]

10)
A) HSO3 is a proton acceptor. Proton acceptor is a base.
B) SO2 is a reductant.
C) 2H+ donated proton to SO3(-2). Hence its base.
D) SO3(-2) is an oxidant.

oxidant is the one that gets reduced itself right?