- Messages
- 2,206
- Reaction score
- 2,824
- Points
- 273
25 ---> 2*10^-3i have problem while solving question number b iii)
your help will be much appreciated
250 --> ?
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
25 ---> 2*10^-3i have problem while solving question number b iii)
your help will be much appreciated
Oh sorry, I meant B. Visual error.It's B
Wow that's a gud thinking xDJust wanna say again I'm not sure but:
If aluminium hydroxide and barium hydroxide are being formed by reaction with water it's probably got to do with OH- ions from water forming dative bond with the metal atoms...
So if there is more such OH- ions in the mixture, there would probably be a higher rate of occurance for this bond formation... Due to random movement and collision and bla bla the high concentration of the OH- increases reaction rate. I suppose. I hope someone else has a more thorough answer.
How did u come up with this overall equation? can u post the method of obtaining the overall equationOh sorry, I meant B. Visual error.
Well here is how you do that,
2NaCl(aq) + 2H2O(l) -------------> 2Na+(aq) + 2OH-(aq) + Cl2(g) + H2(g)
NaOH : 2
H2 : 1
Cl : 1
Half equation method.How did u come up with this overall equation? can u post the method of obtaining the overall equation
moles:I am not getting the ans.. can someone try?
the link mentions the initial anode cathode equations only ..I wanted to know how to arrive at this equation...'' 2NaCl(aq) + 2H2O(l) -------------> 2Na+(aq) + 2OH-(aq) + Cl2(g) + H2(g)''Half equation method.
http://www.gcsescience.com/pt11.htm
Thank you very much25 ---> 2*10^-3
250 --> ?
God knows.the link mentions the initial anode cathode equations only ..I wanted to know how to arrive at this equation...'' 2NaCl(aq) + 2H2O(l) -------------> 2Na+(aq) + 2OH-(aq) + Cl2(g) + H2(g)''
How did u come up with this overall equation? can u post the method of obtaining the overall equation
Hell ya :/There is no need to do the half equations if you are unsure. Clues are already provided in the question stem.
Reactants: NaCl and H2O
Products: NaOH, H2 and Cl2
NaCl + H2O --> NaOH + H2 + Cl2
Alls thats left to do is to balance the equation.
Oh... thankyouIt's probably A, strong acid + strong base = highest enthalpy, weak acid + strong base = lower enthalpy and so on.
Carbon's ox no is +4, so +4+(2*-x)= 0Whats is the oxidation of S in CS2? The answer says —2 but i calculated myself i got +1
Whats is the oxidation of S in CS2? The answer says —2 but i calculated myself i got +1
Helppp!!!!!!!!!!
Correct answer is A.
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now