Chemistry: Post your doubts here!

[princess Anu]

Is it A?

No it's C

 

[nehaoscar]

C, since CO2 is not polar

Could you please explain a bit more?
I mean like the others are not polar either right?

 

[nehaoscar]

Q38..

https://sg.answers.yahoo.com/question/index?qid=20120820030922AAFoXOO

 

[Xaptor16]

View attachment 54323
For optical isomerism, you need a carbon with a chiral center ( 4 different substituents on the C)
As you can see only 1,2 and 3 have a chrial carbon (marked red)
So it is B

It burns readily, so there will be a high concentration of CO2 in the equilibrium mixture. Therefore, applying the formula for equilibrium constant, we can deduce that the value is likely to be high.

thankyou so much

 

[ciephobia]

http://maxpapers.com/wp-content/uploads/2012/11/9701_s14_qp_11.pdf
i need help with question 8^. why can't the temperature be 398k?
thanks in advance.

 

[The Sarcastic Retard]

http://maxpapers.com/wp-content/uploads/2012/11/9701_s14_qp_11.pdf
i need help with question 8^. why can't the temperature be 398k?
thanks in advance.

Exothermic reactions favour low temeperatue and low Ph till I know.. Is it A?

 

[nehaoscar]

How to do this?

 

[ciephobia]

Exothermic reactions favour low temeperatue and low Ph till I know.. Is it A?

yes it is A.
thankyou

 

[nehaoscar]

http://maxpapers.com/wp-content/uploads/2012/11/9701_s14_qp_11.pdf
i need help with question 8^. why can't the temperature be 398k?
thanks in advance.

Exothermic reactions favour low temeperatue and low Ph till I know.. Is it A?

I think that Exothermic reactions favour low temeperature applies only when in equilibrium
So in normal reactions rate will be reduced as temperature is decreased?

 

[The Sarcastic Retard]

yes it is A.
thankyou

I am not sure for pH.. wait for some1 to answer

 

[ciephobia]

View attachment 54426
How to do this?

hey i found this explanation on a thread.

 

[ciephobia]

I think that Exothermic reactions favour low temeperature applies only when in equilibrium
So in normal reactions rate will be reduced as temperature is decreased?

well yes, this sounds good.

 

[ciephobia]

I am not sure for pH.. wait for some1 to answer

ph is 7, that is neutral.

 

[nehaoscar]

hey i found this explanation on a thread.

But then how do you know that definitely 0.25 of propene and 0.25 of methane are formed?
Like it could be 0.1 and 0.4 or anything right?

 

[Mathemagical]

ph is 7, that is neutral.

I'm not too sure about this myself, but there are 2 products which are hydroxides and if the pH were 14 there would be a greater concentration of OH- ions in the solution and the hydroxides would form more readily.

 

[Mathemagical]

But then how do you know that definitely 0.25 of propene and 0.25 of methane are formed?
Like it could be 0.1 and 0.4 or anything right?

This question involves trial and error and balancing equations. It could be 1:4, but then the molecule would have a lot of carbon atoms and is not included in the options available.

 

[ciephobia]

how do i get the answer

 

[nehaoscar]

Why B? Why not C?

 

[ciephobia]

View attachment 54431
Why B? Why not C?

diagnol relationship; beryllium is diagnol to aluminium in the periodic table.

 

[nehaoscar]

diagnol relationship; beryllium is diagnol to aluminium in the periodic table.

Whoa i wasn't taught this! Does this apply to all elements?