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Answer is C.. it cant be A.. Its covenant and metallic respectively.What is the Ans?
In C both is mettali.
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Answer is C.. it cant be A.. Its covenant and metallic respectively.What is the Ans?
What about B and D?Answer is C.. it cant be A.. Its covenant and metallic respectively.
In C both is mettali.
A : Al = Metallic; P = Covalent.What about B and D?
thats what i was wandering ... it cant be C ... and the ans is DA : Al = Metallic; P = Covalent.
B : Cl = Covalent(Diatomic) ; Ar = Van der waals force (Noble gas)
C : Mg = Metallic ; Si = Covalent.
D : S and Cl have covalent bonds.. Its D.
I am sorry, I didn't read the question properly plus got on with the flow!!thats what i was wandering ... it cant be C ... and the ans is D
Ans C?View attachment 54479
What would each one give?
And i think the ans was even marked wrongly on the question ... and its okayI am sorry, I didn't read the question properly plus got on with the flow!!
A?http://freeexampapers.com/A-Level/Chemistry/CIE/2002-Nov/9701_w02_qp_1.pdf
Question 11 .. help please ...
Thats what i meant by saying got on with the flow.. xDAnd i think the ans was even marked wrongly on the question ... and its okay
even i thought A .. but the ans is D :/
LooooooooooooooooooooolThats what i meant by saying got on with the flow.. xD
I got D...even i thought A .. but the ans is D :/
Yeah sorry it is D!And i think the ans was even marked wrongly on the question ... and its okay
Yes it's C... what would the reactions be?Ans C?
Kp = p(H2)*p(I2)/p(HI)^2Loooooooooooooooooooool
Thanks alotDeuterium, 2 1H as you can see has an Mr of 2
2g of Hydrgen = 2/1 = 2moles
Using the equation pv=nRT
A = 2g = 2/2 = 1 mole at same V so different values so not correct
B = 4g/2 = 2mol but 2V so not correct
C = 1/1 = 1 mol oh H and 2/2 = 1 mol of Deuterium
Total mol = 2mol and same V = correct
D = 2/1 = 2mol of H and 1/2 = 0.5mol of Deuterium so not correct
Oh wooow Fantastic (Y) MAsha AllahKp = p(H2)*p(I2)/p(HI)^2
If x mol of HI dissociates then you get x/2 mol of I2 and x/2 of H2. Also the amount of HI left is (b-x) mol.
Substitue the values.
Kp = p(x/2)p(x/2)/p(b-x)^2
Simplify it :
Kp = px^2 / 4(b-x)^2
I had some misunderstanding but I got it... so directly copy pasted the solution..Oh wooow Fantastic (Y) MAsha Allah
Thanks alot
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