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we are altering the original experimentView attachment 54481
Why would B - reducing the concentration increase the yield?
which reaction is that ? :SView attachment 54508
Why is 3 wrong?
Can't it be made in a single reaction by blue + red (reactants) to form 3??
hydrazine has N-N single bonds not tripleView attachment 54507
Why is 2 incorrect?
only in C the Cl has disappeared since C-Cl bond is the weakest
Aldehyde + HBr (D represents the isotope deuterium of H)which reaction is that ? :S
the one u mentioned
for the mercury level to rise on the right side we need a high pressure frm X
OMG no :OAldehyde + HBr (D represents the isotope deuterium of H)
Is there such a reaction??
haha ok! Thanks! So it will be addition with NaBH4 first and then nucleophilic subs so 2 steps yeah?OMG no :O
is the answer A ?View attachment 54486
When does it undergo elimination?
Is it when free radical is formed? or when Cr2 bond is broken?
Yes...is the answer A ?
yes thats rytYes...
no the two red spots on the benzene ring isnt chiral....carbon is attached to 3 different groups not fourView attachment 54504
How is it 1... are the ones marked in red not all chiral centres? :/
It will be attached to a H right?no the two red spots on the benzene ring isnt chiral....carbon is attached to 3 different groups not four
No C can only form four bondsIt will be attached to a H right?
Halogenoalkanes undergo Elimination/Dehydration and Nucleophilic substitution. When adding KOH in ethanol (reflux), it forms alkene (elimination reaction) , NaOH in ethanol (reflux) can be used but our teacher preferred to use KOH always, with NaOH in water (reflux) it forms alcohol which is Nucleophilic substitutionyes thats ryt
alkyl halides undergo reduction nd nucleophilic substitution
nd this same compound can undergo further substitution so that more bromine gets added
reduction reaction takes place when alkyl halides react wid NaOH in ethanol under reflux to form alkene
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