- Messages
- 42
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Hello , I wanted to ask if we can write alkyl groups such as methyl (CH3) in skeletal formula
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Can't we find moles likePV = nRT
R and T are constant. So we can write:
PV = kn, where k is just a constant.
n = PV/k
Moles of gas in flask X = 2*1/k = 2/k
Moles of gas in flask Y = 1*2/k = 2/k
Total moles = 4/k
New volume together = 1+2=3
New pressure = kn/V = k * (4/k) / 3 = 4/3Pa
So even if they hadn't mentioned the product catalysing the reaction, the graph would still look the same as the reactants would eventually run out right.?But A and B will run out at some point
View attachment 54555
What would each give as a result with C?
View attachment 54556
Does LiAlH4 give nascent hydrogen?
View attachment 54557
Why is D - the teritary one not affected by the OH concentration?
View attachment 54558
Between what would forces 2 and 3 be?
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Doesn't K2Cr2O7 turn from orange to green ? (2) but only 1 is correct :?
Thats the main product formed initiallySO2 + Ca(OH)2 ---> CaSO3 + H2O
http://postimg.org/image/kv4auw8xd/full/
Can any1 please explain me why option 2 is not considered?
Then it would have been DSo even if they hadn't mentioned the product catalysing the reaction, the graph would still look the same as the reactants would eventually run out right.?
It may give you the correct final answer, however, technically that assumption is wrong, since 1 mole of gas occupies 24 litres only in room temperature and pressureCan't we find moles like
vol given/24 .. i.e...(1/24 + 2/24)?
Ah yes! And say if it was catalysed by a different catalyst... then it would be C right?Then it would have been D
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