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How is 3 also correct?
V3+ = 20 electrons = 1s2 2s2 2p6 3s2 3p6 4s2 ... so it doesn't have unpaired electrons :/
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If there was already a catalyst present, and the amount of catalyst remained the same, the shape would still be like that of D. Only the value of rate at specific timings would be different. (higher)Ah yes! And say if it was catalysed by a different catalyst... then it would be C right?
Yep only those particular onesSo the reagents could be PCl5 or SOCl etc...?
Heres the intermediate. As you can see the oxygen carries a negative charge and since it has a lone pair it acts as a nucleophile.View attachment 54569
How are 2 and 3 also correct?
What is the intermediate formed? Like it's formula?
Thank you so muchOption 2 is a salt, so it will be found in the flask. The question specifies on the distillate.
You forgot 3d.
How is 3 also correct?
V3+ = 20 electrons = 1s2 2s2 2p6 3s2 3p6 4s2 ... so it doesn't have unpaired electrons :/
Group II metal sulphate solubility decreases down the group, so Barium will give a white precipitate (insoluble)View attachment 54563
Why not the others? what would they give?
3x10^-3 reacts with 2x10^-3 so 3 moles of TlNO3 reacts with 2 moles of NH4VO3. Each Ti will give 2 electrons, giving 6 electrons in total. V in Vo3- is +5, so those 6 electrons will be divided between 2 VO3s, each will get reduced to +2.View attachment 54564
How to do??
View attachment 54565
Why won't amide ions be present?
None. Hydrogen doesn't usually have neutrons, hence the 1 atomic mass.View attachment 54566
I know that 3 is wrong obviously
But the 1H3+ ion ... does it have -2 neutrons?? Like how many neutrons does it have?
View attachment 54571
How to do????
Why would it have 3 bonds? It has 4. (2 with one carbon, 1 with the top ethyl group, 1 with the bottom one) Besides, if it was B, then it would still possess cis-trans isomers.View attachment 54575
Why and how D?
If it's D then the Carbon before the R will only have 3 bonds :O
Why not B?
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