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Chemistry: Post your doubts here!

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How is 3 also correct?
V3+ = 20 electrons = 1s2 2s2 2p6 3s2 3p6 4s2 ... so it doesn't have unpaired electrons :/
 
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Ah yes! And say if it was catalysed by a different catalyst... then it would be C right?
If there was already a catalyst present, and the amount of catalyst remained the same, the shape would still be like that of D. Only the value of rate at specific timings would be different. (higher)

The thing with this question is that since the product themselves are catalysing the reaction, the amount of catalyst increases over time, instead of being constant.
 
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I know that 3 is wrong obviously
But the 1H3+ ion ... does it have -2 neutrons?? Like how many neutrons does it have? :confused:
 
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why is 2 wrong?
More H+ concentration = more acidic ... so why is it wrong?
 

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Help please........ the ans is B

Which of these equations represents the reaction of sulphur dioxide with an excess of aqueous

sodium hydroxide?

A SO2 + NaOH ----> NaHSO3

B SO2 + 2NaOH -------> Na2SO3 + H2O

C SO2 + 2NaOH ------> Na2SO4 + H2O

D SO2 + 2NaOH -----> Na2SO4 + H2

Why cant it be reaction C???
 
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upload_2015-6-4_16-3-44-png.54551

How is 3 also correct?
V3+ = 20 electrons = 1s2 2s2 2p6 3s2 3p6 4s2 ... so it doesn't have unpaired electrons :/
You forgot 3d.

View attachment 54563
Why not the others? what would they give?
Group II metal sulphate solubility decreases down the group, so Barium will give a white precipitate (insoluble)

3x10^-3 reacts with 2x10^-3 so 3 moles of TlNO3 reacts with 2 moles of NH4VO3. Each Ti will give 2 electrons, giving 6 electrons in total. V in Vo3- is +5, so those 6 electrons will be divided between 2 VO3s, each will get reduced to +2.

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Why won't amide ions be present?

They will form NH3 immediately.

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I know that 3 is wrong obviously
But the 1H3+ ion ... does it have -2 neutrons?? Like how many neutrons does it have? :confused:
None. Hydrogen doesn't usually have neutrons, hence the 1 atomic mass.


Mass of gas is 1.32g, and usually NO2:O2 ratio is 4:1. So, taking mass of no2 as x, and O2 as 1.32 - x, you get (x/46) / ((1.32-x)/32) = 4. Solving which gives you x = 1.12g. 1.12 / 46 gives 0.0243 something. Ratio of MO:NO2 is 1:2, so nMO = 0.0122. 0.0122 = 2-1.32 / Mr gives you Mr = 55.9 almost. 55.9 - 16 gives you around 39.9, which is very near to the atomic mass of Ca. (you will get 40.1 if you don't round off things)
 
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Why and how D?
If it's D then the Carbon before the R will only have 3 bonds :O
Why not B?
 
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