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Chemistry: Post your doubts here!

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heyy!
can someone explain this please
Alkane X has molecular formula C4H10. X reacts with Cl 2(g) in the presence of sunlight to produce only two different monochloroalkanes, C4H9Cl. Both of these monochloroalkanes produce the same alkene Y, and no other organic products, when they are treated with hot ethanolic KOH. What is produced when Y is treated with hot concentrated acidified KMnO4?
A CO2 and CH3CH2CO2H
B CO2 and CH3COCH3
C HCO2H and CH3COCH3
D CH3CO2H only
The answer is B, why not A?
The chloroalkenes formed will have 2 methyl branches, only then alkenes formed by both isomers will be same.
 
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heyy!
can someone explain this please
Alkane X has molecular formula C4H10. X reacts with Cl 2(g) in the presence of sunlight to produce only two different monochloroalkanes, C4H9Cl. Both of these monochloroalkanes produce the same alkene Y, and no other organic products, when they are treated with hot ethanolic KOH. What is produced when Y is treated with hot concentrated acidified KMnO4?
A CO2 and CH3CH2CO2H
B CO2 and CH3COCH3
C HCO2H and CH3COCH3
D CH3CO2H only
The answer is B, why not A?
THere are two posiblities of forming alkenes in primary Halogenoalkane.
There is only one posiblity of forming alkene in tertiary.
Hence:
WIN_20151104_20_05_02_Pro.jpg
 
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Can u please explain your working? It's going over my head :p
I used trial and error.
I tried option A, didnt satisfied the answer, but B did. Sth like this;
Initial moles of 2P : 2
IM of 2Q and R : 0
Equilibrium moles of R : x
EM of 2Q is x/2 (1:2 ratio)
EM of 2P is 2 - x/2 (1:2 ratio and IM was 2 so we will subtrct x/2)
So addition of EM = 2 - x/2 + x/2 + x = 2 + x
 
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I used trial and error.
I tried option A, didnt satisfied the answer, but B did. Sth like this;
Initial moles of 2P : 2
IM of 2Q and R : 0
Equilibrium moles of R : x
EM of 2Q is x/2 (1:2 ratio)
EM of 2P is 2 - x/2 (1:2 ratio and IM was 2 so we will subtrct x/2)
So addition of EM = 2 - x/2 + x/2 + x = 2 + x
kayy!! thanks bro!
 
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