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Hydrolysis in 2 and 3http://gopapers.net/alevel.html?_9701_w11_qp_12__9701_w11_ms_12
Q39 .. what do they mean by acidification??
1 cant be.
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Hydrolysis in 2 and 3http://gopapers.net/alevel.html?_9701_w11_qp_12__9701_w11_ms_12
Q39 .. what do they mean by acidification??
CH3SH + 3O2 ----> CO2 + SO2 + 2H2Ohttp://gopapers.net/alevel.html?_9701_w11_qp_12__9701_w11_ms_12
Q13 ... won't the SO2 oxidise to form SO3 ??
so i should know this ... thanksCH3SH + 3O2 ----> CO2 + SO2 + 2H2O
okHydrolysis in 2 and 3
1 cant be.
The chloroalkenes formed will have 2 methyl branches, only then alkenes formed by both isomers will be same.heyy!
can someone explain this please
Alkane X has molecular formula C4H10. X reacts with Cl 2(g) in the presence of sunlight to produce only two different monochloroalkanes, C4H9Cl. Both of these monochloroalkanes produce the same alkene Y, and no other organic products, when they are treated with hot ethanolic KOH. What is produced when Y is treated with hot concentrated acidified KMnO4?
A CO2 and CH3CH2CO2H
B CO2 and CH3COCH3
C HCO2H and CH3COCH3
D CH3CO2H only
The answer is B, why not A?
THere are two posiblities of forming alkenes in primary Halogenoalkane.heyy!
can someone explain this please
Alkane X has molecular formula C4H10. X reacts with Cl 2(g) in the presence of sunlight to produce only two different monochloroalkanes, C4H9Cl. Both of these monochloroalkanes produce the same alkene Y, and no other organic products, when they are treated with hot ethanolic KOH. What is produced when Y is treated with hot concentrated acidified KMnO4?
A CO2 and CH3CH2CO2H
B CO2 and CH3COCH3
C HCO2H and CH3COCH3
D CH3CO2H only
The answer is B, why not A?
I am not sure about that one too ... but MgO only dissolves slightly in water and apparently, SiO2 mp/bp is lower than that of MgO givenView attachment 57505
please explain why P is MgO... isn't MgO supposed to be soluble and ionic compounds conduct in aqueous sol..?
It will replace H of OH only.
Can u please explain your working? It's going over my head
I used trial and error.Can u please explain your working? It's going over my head
kayy!! thanks bro!I used trial and error.
I tried option A, didnt satisfied the answer, but B did. Sth like this;
Initial moles of 2P : 2
IM of 2Q and R : 0
Equilibrium moles of R : x
EM of 2Q is x/2 (1:2 ratio)
EM of 2P is 2 - x/2 (1:2 ratio and IM was 2 so we will subtrct x/2)
So addition of EM = 2 - x/2 + x/2 + x = 2 + x
sorry didnt get uhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w12_qp_12.pdf
q:17 ... why can't i just cross multiply the number of moles for M? and then use n=mass/Mr to find Mr?
why does it give a different answer?
View attachment 57506
i have replied to you on the other thread .. well, above all, ask Allah to help you remember and stay confident, you will do well iA.any tips to remember the organic reactions? anyone plz! ..I often mix them up
The concentration increases with time. At first, it rapidly increases as there are more reactant molecules so more frequent collisions and then it slows down, gradually stopping as reactants decrease and is eventually used up.
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