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Chemistry: Post your doubts here!
- Thread starter XPFMember
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No, don't worry, I do not think you need to know it for A-levels. I just answered since I studied about it in biochemistry.
Just for general knowledge, EDTA stands for Ethylene-Diamine-tetra-Aceticacid and is either used as an anticoagulent (prevents blood clots) for preserving blood specimens or as a chelating agent that binds calcium with other metals.
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Ah I see! Thank youNo, don't worry, I do not think you need to know it for A-levels. I just answered since I studied about it in biochemistry.
Just for general knowledge, EDTA stands for Ethylene-Diamine-tetra-Aceticacid and is either used as an anticoagulent (prevents blood clots) for preserving blood specimens or as a chelating agent that binds calcium with other metals.
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Whatever is not absorbed is the color of the substance.
For C, 650nm is least absorbed so color is red.
For D, 450nm is least absorbed so it's blue.
Isn't it 400 for D ?
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But violet isn't in the option
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Thanks.Here you go. It would be a really crowded structure in a space fill model.
how about this question ?
Value in c(i) is 7 x 10^-7 . in the mark scheme it's written concentration of product if 0.1 but shouldn't it be 0.1 - (7 x 10^-7 )?
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Why will u do that?how about this question ?
Value in c(i) is 7 x 10^-7 . in the mark scheme it's written concentration of product if 0.1 but shouldn't it be 0.1 - (7 x 10^-7 )?
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You made ur equation of Kc.how about this question ?
Value in c(i) is 7 x 10^-7 . in the mark scheme it's written concentration of product if 0.1 but shouldn't it be 0.1 - (7 x 10^-7 )?
Just substitute the values and find [NH3(aq)]
o.1 is conc of silver nitrate soln and (7 x 10^-7 ) is conc of Ag.
Yes but we need to use the concentration of Ag(NH3)2 not of silver nitrate
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Can anyone plz explain me why the answer for chemistry may june 2007 v1 p1 first answer is C?= (Mass no x Relative Abundance) / (Relative Abundance)
= {(10 * 1) + (11 * 4)} / 1 + 4
= 10.8
There is no peak for the mass no. 12, so we don't need to consider it. Note: Even if you consider it, it will be 12 * 0 = 0
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From part (a) you can see that there is no effect of Cl- ion on production of O2 where as if u see the reaction of chlorine the equilibrium shifts to form more chlorine and moves in direction of electrons thus the E value will be less positive that is it will decrease.
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I believe the CD has been uploaded here before, so you could find it by using the search bar in xtremepapers. If not, here is a torrent link for the CD.