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9701_w09_qp_42
qtn 5(a)
can someone plzz explain me this part?
Here in this question, it isn’t based on what we studied throughout the year’s course, its more like enough information is given in the question, and based on this you have to make your answers. In the question there are 2 principals we got to know about.
1st is that a delocalised benzene is coplanar, while any other cycloalkane isn’t.
2nd is that a simple chain with no methyl branches is coplanar while a methyl branched one isn’t.
So far nothing we have learned all from the question and you just have to conclude.
For the structures given we have to apply the knowledge we gained.
In A its all benzene rings, so its coplanar (1st principal)
In B there is a cycloalkane attached which makes it not all carbons coplanar. (1st)
In C this is somehow complicated but it is coplanar, thats because both of the side chains attached to the O has no branches and are straight chains making them coplanar (2nd)
In D its just a simple chain without methyl branches so all coplanar (2nd)
And in E Its a benzene ring attached to a non-methylbranched chain, which makes it coplanar. (1st & 2nd)
Get it?