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Chemistry: Post your doubts here!

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36 When the yellow liquid NCl3 is stirred into aqueous sodium hydroxide, the reaction that occurs
can be represented by the following equation.
2NCl3(l) + 6NaOH(aq) → N2(g) + 3NaCl (aq) + 3NaOCl (aq) + 3H2O(l)
What will be the result of this reaction?
1 The nitrogen is oxidised.
2 A bleaching solution remains after the reaction.
3 The final solution gives a precipitate with acidified silver nitrate.

why is 1) not correct
 
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71
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36 When the yellow liquid NCl3 is stirred into aqueous sodium hydroxide, the reaction that occurs
can be represented by the following equation.
2NCl3(l) + 6NaOH(aq) → N2(g) + 3NaCl (aq) + 3NaOCl (aq) + 3H2O(l)
What will be the result of this reaction?
1 The nitrogen is oxidised.
2 A bleaching solution remains after the reaction.
3 The final solution gives a precipitate with acidified silver nitrate.

why is 1) not correct
The ox.no of N in NCl3 is +3 and in N2 it is 0
change in ox.no=3 so N has GAINED 3 electrons so it's been reduced and that's why 1 is not correct and hence C is the right answer
 
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X is an element in Period 2. In which fluoride is the F–X–F angle the largest?
A BF3 B CF4 C NF3 D OF2
 
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Reaction score
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Points
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The ox.no of N in NCl3 is +3 and in N2 it is 0
change in ox.no=3 so N has GAINED 3 electrons so it's been reduced and that's why 1 is not correct and hence C is the right answer

But Nitrogen is more electronegative than chlorine so shouldn't Nitrogen be -3 and Chlorine be +1 (Br<Cl<N<O<F)
 
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438
Reaction score
3,645
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253
You just need to understand these:

Pressure is DIRECTLY PROPORTIONAL to Temperature p=nt
Pressure is INDIRECTLY PROPORTIONAL to volume p=n/v where n is a constant

from there you derive the equations :p1V1=P2V2, P1/T1 = P2/T2, P1V1/T1 = P2V2/T2

Its pretty simply if you can understand the relationship!!!:D:D:D

hope that helps:)
thanks
 
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http://papers.gceguide.com/A Levels/Chemistry (9701)/9701_w16_qp_13.pdf
Please Explain :
Q 3 ,20, 37 and 16

First look at Q 16


Write eq… of decomposition of Mg(NO3)2

2 Mg(NO3)2------------ 2 MgO + 4 NO2 + O2

He wants mass of oxide of Nitrogen ,X

Now find Mr of Mg(NO3)2 i.e = 148.3

Finding moles = 7.4/148.3

= 0.05 moles

Look at the mole ratio of NO2 and Mg(NO3)2 you get

2:4

= 1:2

So moles of NO2 = 0.05*2

= 0.1 moles

To find the mass of NO2 we need MR of NO2 i.e. =46

Finally, Mass = 46*0.1

= 4.6 g
 
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Someone from here actually told us the trick before

Take the two equations from the data booklet and balance the two equations

1496433028883.jpg
 

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