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no imagei need a help in this question why is it A?
no image
So it can't be B r8When ever two stages are involved in reaction its ethalpy profile diagram will have two humps in its graph .......as it is stated in the question X-Y is positive thus it will be endo and reactants will have low energy than the products....in Y-Z ethalpy change is neg thus its exo and reactants will have high energy than products as shown in option A
So it can't be B r8
2Al+Ba(NO3)2--->Al2O3+Bao+N2
Mole of Ba(NO3)2= 0.783/(261)=3x10^-3 mole
Mole of N2=mole of Ba(NO3)2= 3x10^-3 mole
1 mole--->24 dm^3
3x10^-3= 24x(3x10^-3)=0.072 dm^3
0.072dm^3=72 cm^3.
the answer is B. right?
Can anyone help me please?
What is involved in the mechanism of the mechanism of the reaction between aqueous sodium hydroxide and 2-bromo-2-methylbutane?
A heterolytic bond fission, attack by an electrophile on a carbanion
B heterolytic bond fission, attack by an nucleophile on a carbocation
C homolytic bond fission, attack by an electrophile on a carbanion
D homolytic bond fission, attack by an nucleophile on a carbocation
The balanced equation should be 10Al + 3Ba(NO3)2 = 5Al2O3 + 3BaO + 3N2 , right? therefore we will get a different answer..
plz reply as soon as possible..
Can you answer my question please?I don't have the context of the full question.
But in both equations, the ratio of Ba(NO3)2 and N2 happens to be 1:1. Therefore, it's a coincidence that the answers ended up to be the same.
Can you answer my question please?
are you talking about this question
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