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Chemistry: Post your doubts here!

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Water wasn't specifically mentioned but I'm not sure about this equation
If water wasn't mentioned, then I think this equation will work.. I wrote NH3 + H2O <---- ------> NH4+ + OH- .. you can see that NH4 + has donated a proton to OH- and has thus formed NH3 + H2O.. if i am not wrong..
however, not sure whether water was mentioned or not..
 
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well yes they make a balanced paper for those who appear in the same session so that the threshold is not too high nor too low
so this could be a possibility
So this means if there was only 10% organic in P2 then most of the P4 will be organic based as normally 60% is organic in P4 ?!!
 
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Last question the structure of L too please
 

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For b why is n=1 should it be n=2 ??
For b why is n=1 should it be n=2 ??[/QUOTE]
my weird method
ok so in the question its clearly stated that cr-cl in the complex does not react . hence the values given in the table are for cl(3-n) that reacts with ag . so now the moles you calculated in the previous question (3.75*10^-3) compare that with each isomer . For A its 1:1 ( same moles ) so we have to make the cl outside the complex =1 and to do that we make n =2 . for isomer b it's 1:2 (7.5/3.75) that means that there will 2 chlorine that react hence to make cl2 we need to make n = 2
 
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so just clarify something with me the 4.0 peak is due to ch-o yes ? because ms says just ch but just ch chemical shift isnt in that range
 

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for b (ii) ms states that remaining is 10.8/1000 * 0.5 but isnt the amount reacted equal to that ???!
 

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for b (ii) ms states that remaining is 10.8/1000 * 0.5 but isnt the amount reacted equal to that ???!
Imagine:
100 units of NaOH is reacted with SO2 and HCl. 90 units was consumed in this reaction. 10 units of NaOH remains in the solution.

This is called EXCESS NaOH was reacted with SO2 and HCl.


Now in real life we don't know that 90 units of NaOH reacted with SO2 and HCl. What we know is that we started with 100 units.

By doing titration with the remaining solution soup, we can know that 10units of NaOH REMAINED in the solution. This is the excess amount.


Using the above two information, we can do the magic: 100-10= 90 units of NaOH.
 
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for NMR, say that the peak splits into three, so there are 2 H on the adjacent carbon atom but what if there are two adjacent carbon atoms?
 
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