• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Chemistry: Post your doubts here!

Messages
1,594
Reaction score
483
Points
93
Silent Hunter said:
http://www.xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9701%20-%20Chemistry/9701_s07_qp_2.pdf

Q2 (c)

How to do after this:

(0.1 + x )^2 = 4
(0.5 - x)^2
Square root both sides in an attempt to solve the equation for x.
=> (0.1 + x)/(0.5 - x) = 2
=> x = 0.3
Insert x into your expressions for equilibrium moles: (0.1 + 0.3) = 0.4 and (0.5 - 0.3) = 0.2.
 
Messages
57
Reaction score
2
Points
8
Silent Hunter said:
http://www.xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9701%20-%20Chemistry/9701_s04_qp_1.pdf

Q1

help please.Paper tomorrow :(
 

Attachments

  • solution 12.jpg
    solution 12.jpg
    70.2 KB · Views: 294

Nibz

XPRS Moderator
Messages
4,615
Reaction score
9,574
Points
523
^ To get the moles of one atom present in that molecule.
In CO2 -> One Carbon atom and 2 Oxygen atoms. So x 3
In Methane -> One Carbon atom and 4 Hydrogen atoms. So x 5
Likewise, in Neon there is only one. So x1 and in Ozone there are 3 Oxygen atoms. So x3
 

Nibz

XPRS Moderator
Messages
4,615
Reaction score
9,574
Points
523
Final Pressure = pHe + pNe
=> (Volume of He/Total Volume) x Pressure of He + (Volume of Neon/Total Volume) x Pressure of Neon
=> (5/15) x 12 + (10/15) x 6
=> 4 + 4 = 8 kPa
Answer A
 
Messages
1,532
Reaction score
478
Points
93
Silent Hunter said:
http://www.xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9701%20-%20Chemistry/9701_w10_qp_12.pdf

Q11

All the questions you have posted require the same concept. So you should first concentrate on correcting your concept instead of solving more questions. Here is a simple way to get hold of it. Use the terms initial amount, amount reacted, amount formed and equilibrium amount to tackle such questions. The question is solved in the following way:
 

Attachments

  • mole.png
    mole.png
    13.4 KB · Views: 316
Top