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Chemistry: Post your doubts here!

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the strongest bond to break will require the highest energy to break, and thus will linger around for the longest. That should help you from the chemistry point of view, though biologists would have learnt to compare their strength also. Ionic bonds in general are stronger than disulphide bonds.

If anyone need A Level chemistry help, consider subscribing to my YouTube channel, as linked in the post above.
 
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Bu
the strongest bond to break will require the highest energy to break, and thus will linger around for the longest. That should help you from the chemistry point of view, though biologists would have learnt to compare their strength also. Ionic bonds in general are stronger than disulphide bonds.

If anyone need A Level chemistry help, consider subscribing to my YouTube channel, as linked in the post above.
but the answer is A , how?
 
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Bu

but the answer is A , how?
I guess the covalent S-S bond is indeed stronger than the zwitterionic interactions. I mean in chemistry, when you have to break covalent bond in the sense of a giant molecular lattice network, that takes roughly the same or even larger amount of energy to break, i.e. to melt a giant ionic framework.

You must have covered this in biology classes specifically in terms of these bond strengths. I do stand corrected that the covalent S-S bond can indeed be on the same level as the zwitterionic interactions (which are obviously not as strong as a cationic metal and anionic metal interactions)..
 
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Hi all, I have added more short tutorial videos covering specific concepts, like quick-bites with worked examples, explaining step-by-step how to proceed with calculations/explanations. These complement the longer videos that cover full past paper tutorials.


My videos/YouTube channel try to achieve more than just solving a paper or following mark scheme. Some have found some mistakes within, which is good. The viewers are learning! I don't usually try to correlate to mark schemes, and hey mistakes are common, but I try to minimise mine of course.

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Can you help with this please?
 

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Help please!!!

Well you should always have tried something, i.e. outline your ideas then people can just help to guide you along. Remember, if you don't do that and just rely on someone explaining from zero, you risk losing it all big time in the real exam. By then it becomes too late.

Go for option 2 => since these involve specific isotopes, they both have mass of 34. Even if you remove some of the dioxygen, the average mass will remain the same.

Check number 1. Same deal with option 2. Average mass will just be 34 because all the molecules present have mass of 34.

Check number 3. H2S + 3/2 O2 --> SO2 + H2O (to balance the eqn - gcse/o level, no). I leave you to think about limiting and excess reactant based on the reacting mole ratio, and the information that you have equal number of these two molecules in the mixture. It all comes down is 3 correct or not.
 
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Since $$H_2SO_4$$ is a strong acid it will dissociate fully into $$H^+$$ ions, $$HSO_4^-$$ is the conjugate base and further dissociates into $$SO_4^{2-}$$ ions and protons therefore the solution wont contain an equal number of $$H^+$$ and $$HSO_4^-$$ ions so 2 is incorrect, hence since 2 is incorrect the only option available is D.

Also wait r u from sir shoukats class because i swear i just answered this question there rn
 
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Anyone doing CIE Chemistry variant 13?
Check out my full Paper 1 tutorials, and enjoy my take on thinking out loud through the different papers. It is more important to be able to work things out than simply doing without understanding why and the how.

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Subscribe and share with friends, class group chats, juniors/seniors from school, anyone else you think the channel might be useful for. Cheers.

 
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chemistry past paper mayjune 2011 paper 22. (s11_22).
number 1. 1ci.
I still couldn't process why it is directly 0.04. I thought 0.04 reacted so why didn't it subtract 1-0.04 = 0.06 for ethanoic acid?
 
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i have attached two files here: a question paper and its markscheme. Please do help me with number 6b as soon as possible. Why 19.10 (which I think is got directly from the titre of titration 5). Why not sum up all titre values then divide by 5, I had got 19.23? How am I calculating wrong, or where am I not understanding the question?
 

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http://www.xtremepapers.com/CIE/Interna ... _qp_11.pdf

number 4. Why is the answer C and not D? With a catalyst, activation energy is lowered isnt it? :pardon:
in diagram 1, the higher temperature must be Q due to more molecules with high energy/ energy greater than ea, and less molecules with low energy.
in diagram 2, yes catalyst lowers the Ea, so only a small value of molecular speed is required for particles to make successful collisions. Less Ea, less speed necessary for particles. So it's X.
Thus C.
 
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http://www.xtremepapers.com/CIE/Interna ... _qp_11.pdf

number 4. Why is the answer C and not D? With a catalyst, activation energy is lowered isnt it? :pardon:

in diagram 1, the higher temperature must be Q due to more molecules with high energy/ energy greater than ea, and less molecules with low energy.
in diagram 2, yes catalyst lowers the Ea, so only a small value of molecular speed is required for particles to make successful collisions. Less Ea, less speed necessary for particles. So it's X.
Thus C.
 
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