i did answer to that part, b/c examiner stated ratio of I:ZnFOR B) The values calculated should not be less than the values used to calculate! So for this, all readings are to 2 dp so the values used to calculate the mass of iodine are all to 2dp ours should be as well! The trick is always to do equal dp as readings UNLESS stated otherwise (like sometimes they say (3sf) specifically so follow that in that case!
-AS for the second part I'm slightly confused with that also! Can't seep to find a logical reason! xhizors ?
-I think the logical way here, rather the Intuitive way was to calculate I:Zn as we need an answer of 2 for that! Because I:Zn ratio would be 2 if exp showed its validity. That's the only logical reason I can think of!
-ANOMALIES: IF I:Zn ratio differs from the rest by a lot it is an anomalous result!
-If I:Zn is too high (meaning mass ofZn was too low) then means Zn must've been blown out of tube while heating!
-If I:Zn too low (meaning mass if Zn too high) maybe not dried enough!
Any other confusions?