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Chemistry: Post your doubts here!

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Why is it C? please explain bro
it shows 0.25 mole of X are reduced and acording to molar ratio Y should be increased by (2 times the value of the the amount of X converted ) hence it had to be C or D now put these values in the equation Kc=(0.5)^2/0.25 you will get 1 hence the answer is C
 
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37 Which compounds may result from mixing ethane and chlorine in the presence of sunlight?
1 CH3CH2Cl
2 CH3CH2CH2CH3
3 CH3CHCl CHCl CH3

Can anyone explain to me why is the answer A (1,2 and 3 is correct)
1 is simple momo substitution
2) two ethane radicals have combined(termination step)
3) two chloroethane radicals combined(termination step)
 
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The answer should be B.

D is showing the overlap of four orbitals, and is hence showing a square-planer arrangement. (Hint hint: XeF4). We all know that XeF4 contains 4 sigma bonds, regardless of what the diagram is showing. Hence, D is not the correct answer, rather a smartly made confusing option.
(y) awesome bro didnt think about it that way :/
 
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The answer should be B.

D is showing the overlap of four orbitals, and is hence showing a square-planer arrangement. (Hint hint: XeF4). We all know that XeF4 contains 4 sigma bonds, regardless of what the diagram is showing. Hence, D is not the correct answer, rather a smartly made confusing option.

i dont get it
 
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Q2
first find mass of nitrogen in 14g of fertilizer by
15/100 x 14=2.1g
then find mole=2.1/14(Mr or nitrogen)=0.15mol
then since con=mol/vol=0.15/5=0.03mol/dm3


Q27
all of them wud have had molecular formula C10H14O
so nw read second statement that its unreactive towards mild oxidizing agents...which clearly tells that X is tertiary alcohol
so the only possibility is D,since if u again break the bonds to attach H and OH,the OH can be attached to carbon atom which in turn is attach to 3 other carbon atoms.


hope it helped!
 
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ques
question 10
at initial stage pressure 1 atm
volume is 100%
at equilibrium h20-->80%
h2-->20%
02-->10%
total------>110%=1.1
partial pressure h20-->80%/110% *1=0.8/1.1
h2-->20%/110% *1=0.02/1.1
02-->10%11% *1=0.1/1.1


question 31 1)is wright because u should watch out how the arrows are going so u will see from u-->R u go from U to S to R so its like -(92)-(-134) u get +42
2) twi is wrong because when u go from t-->s -75-(92)=-167 and they said its endothermic which should be positive ,so its wrong
3)r to t (-134)+(92)-(-75)=33 and in the question its with negative so ofc its wrong
 
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question 2 10cm3 of cs2 and 30cm3 of 3o2 ,they r equal to the number of moles ,and 10cm3 of co2,and 20 of so2
then they said 50 cm3 of oxygen but only 30 reacted so 20 are left ,this 20cm3 of oxygen left u add them with 10cm3 and 20cm3 of co2 and so2 so u get 50 sm3 of gas after burning
and for the volume of gas after adding naoh im not sure but i guess because of when naoh rects with the products it gives 2NAOH +SO2+CO2+NA2CO3+H2CO3 SO2 and so2 and co2 reacts so 20 is left from naoh

question 30
number of moles of ethanol is 0.65 and for ethanoic acid is 0.5
and the mass for ch3co2ch2ch3 is 0.5*82=44
they want the yield of ester so the mass of ethanoic acid 22/44*100
 
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Nov 2005-- only one bcoz any molecule can contain isotopes so only radius will be the same in all isotopes and nucleon no: and relative isotopic mass will be different..

Oct 2003-- Q23 , its not A bcoz bromine would not react with this alkane bcoz it is saturated.. not B bcoz Cl would substitute Br which is attached to the third group and the removed Br would not take place of any H of the first carbon...not D bcoz we dont need Cl on the first carbon.. so its C ..

june 2004-- Q9 they asked for same conc. of hydrogen as HCL which is a strong acid.. its not A bcoz A is a weak acid , not C bcoz its an alkali so no H+ ions.. now the formula for sulphuric acid is H2so4 so its contains 2 H+ ions and HCL has only one H+ ion.. so it will be nitric acid HNO3 containing one H+ ion..
 
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question 2 10cm3 of cs2 and 30cm3 of 3o2 ,they r equal to the number of moles ,and 10cm3 of co2,and 20 of so2
then they said 50 cm3 of oxygen but only 30 reacted so 20 are left ,this 20cm3 of oxygen left u add them with 10cm3 and 20cm3 of co2 and so2 so u get 50 sm3 of gas after burning
and for the volume of gas after adding naoh im not sure but i guess because of when naoh rects with the products it gives 2NAOH +SO2+CO2+NA2CO3+H2CO3 SO2 and so2 and co2 reacts so 20 is left from naoh

question 30
number of moles of ethanol is 0.65 and for ethanoic acid is 0.5
and the mass for ch3co2ch2ch3 is 0.5*82=44
they want the yield of ester so the mass of ethanoic acid 22/44*100


in Q2 there is 50 cm^3 of cs2 not 30.. thn how will we do it??

and in q 30 why did we multiply 0.5 into 30??
 
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