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ClF4(minus1).gifwhat will be the structure of ClF4-?
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ClF4(minus1).gifwhat will be the structure of ClF4-?
How to name organic compounds with more than one functional group?
which functional groups are chosen as to give them the least number? and is it necessary for both or all of the functional groups to be on the longest chain ?
http://maxpapers.com/wp-content/uploads/2012/11/9701_s09_qp_2.pdf
variant 1
qs 2)ii) Why do we add to find the enthalapy change? why nt subtract?
suppose if there is a compound with carboxylic acid and ketone group.. so I'll try to name as such both the functional groups are a part of the longest chain..? and if thats not possible, at least carboxylic acid should be .. right?When there are more than 1 functional groups, there is a need to rank the functional groups.
http://www.masterorganicchemistry.co...-nomenclature/
suppose if there is a compound with carboxylic acid and ketone group.. so I'll try to name as such both the functional groups are a part of the longest chain..? and if thats not possible, at least carboxylic acid should be .. right?
Moreover what's the use of the prefix??? for example ester prefix is ''oxycarbonyl'' and aldehyde's is OXO but we do not use these terms to name esters/aldehydes right? so what is their purpose
http://www.chemguide.co.uk/mechanisms/nucadd/hcntt.htmlIn the reaction of HCN with Carbonyl compounds, we use NaCN as a catalyst or as a source of CN- ions?
In the reaction of HCN with Carbonyl compounds, we use NaCN as a catalyst or as a source of CN- ions?
While making displayed formula, do we have to take care of making the right structure with the correct bond angles too? for example in J10/23Q5 part a, the structure given in the Marking scheme is absolutely perfect in terms of the bond angles etc but when I make displayed formulas generally I tend to just display all the bonds ( not caring about the bond angles)
So is my method acceptable?
It seems correct to me, as for balancing of the stuff in the box it's better to do it but it won't affect your answer.is my cycle correct? (particularly the highlighted part) and do we need to balance it?
Can anyone explain to me these few questions?
1. The density of ice is 1.00gcm-3. What is the volume of steam produced when 1.00cm3 of ice is heated to 323 degree celcius (596K) at a pressure of one atm (101 kPa) [ 1 mol of gas occupies 24.0dm3 at 25 degree celcius (298K) and one atm.
Ans: 2.67 dm3
2.Which of the following would behave most like an ideal gas at room temp?
Ans: Helium (Why Helium not Hydrogen?)
3. What are the assumptions of the kinetic theory of gases and hence of the ideal gas equation, PV= nRT?
Ans: molecules move without interacting with one another except for collisions ( Why does this statement mean?)
4. When a sample of gas is compressed at constant temp from 1500 kPa to 6000 kPa, its volume changes from 76.0cm3 to 20.5 cm3. Which statement are possible explanations for this behavior?
Wrong ans: The gas partially liquefies / Gas is absorbed on to the vessel walls ( Why)?
Thank You.!
Guys, I am struggling with this question!!!! :'(
It's May June 2014, 23 Question 1 (b) (v)
(v) Deduce the values of x, y and z in the equation in (iv)
PLEASE HELP!!!http://maxpapers.com/wp-content/uploads/2012/11/9701_s14_qp_23.pdf
A few key things to note, the gas volumes were measured at 298K and 100 kPa. These are standard conditions. What this means is that the products will have H2O as a liquid. So you can ignore its volume.
CxHy + O2 -----> CO2 + zH2O
First thing you need to know, x moles of C on the left will give x moles of C on the right.
CxHy + O2 ----> xCO2 + zH2O
Next, y moles of H on the left will give z moles of H on the right. Since z = 2H atoms, and since z = y, it will give y/2 H atoms on the right.
CxHy + O2 -----> xCO2 + y/2 H2O
You start off with 10 cm3 of CxHy, and 100 cm3 of O2.
Final volume = 95 cm3. This volume accounts for "unreacted" oxygen and CO2. Since we do not consider the volume of H2O. The unreacted oxygen is because the question mentioned that we used "excess" oxygen.
So 95 cm3 = CO2 + Unreacted O2
They say the CO2 is absorbed by NaOH, and it becomes 75 cm3.
That means the volume of CO2 is 20 cm3.
75 cm3 of Unreacted oxygen is left from 100cm3 used. So we used 25 cm3.
This gives you the following ratios:
CxHy : O2 : CO2 : H2O
10 : 25 : 20 : X
Simplifies to, 1 : 2.5 : 2
So 1 CxHy + 2.5 O2 ----> 2CO2 + H2O
Like above, CxHy ---> xCO2
Which is 2 in this case, so now you have:
C2Hy + 2.5O2 ---> 2CO2 + H2O
Now tackle the oxygens, there's 5 moles on the left. There has to be 5 on the right. Which there are so you end up with:
C2Hy + 2.5 O2 ----> 2CO2 + 1H2O
2 moles of H2 on the right, so there has to be 2 on the left.
Giving you C2H2.
x = 2
y = 2
z = 1
However since they don't like having decimals for values,
It becomes 2 C2H2 + 5 O2 ---> 4CO2 + 2H2O
x=2, y=2, z=2.
They did mention that putting z as 1 is acceptable though.
Hope that helped!
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Thank you so much! You have no idea how grateful I am to you for solving this step by step! THANK YOU!!!!
Yeah.Xylferion You giving AS this session?
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